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I'm trying to stream my webcam from my server to the client. I understand sockets but I don't know what to send... Here is my code for the webcam:

import Tkinter as tk
import cv2
from PIL import Image, ImageTk
import numpy as np
import time


cap = cv2.VideoCapture(0)

cap.set(3,920)
cap.set(4,840)

root = tk.Tk()
root.bind('<Escape>', lambda e: root.quit())
lmain = tk.Label(root)
lmain.pack()

def show_frame():

    _, frame = cap.read()
    frame = cv2.flip(frame, 1)
    cv2image = cv2.cvtColor(frame, cv2.COLOR_BGR2RGBA)
    img = Image.fromarray(cv2image)
    imgtk = ImageTk.PhotoImage(image=img)
    lmain.imgtk = imgtk
    lmain.configure(image=imgtk)
    lmain.after(10, show_frame)

time.sleep(2)
show_frame()
root.mainloop()

I'm guessing it would be something like this: 

f = open('textFile.txt','rb')
l = f.read(1024)
while (l):
  c.send(l)
  l = f.read(1024)
  if l == '':
    break
  f.close()
  c.close()

The above is for a file, I know, but I Can't figure out what "l" should be to send the webcam data to the client. I'm stumped.

user2648117
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  • Here is a very similar SO post to get you started: https://stackoverflow.com/questions/30988033/sending-live-video-frame-over-network-in-python-opencv – LeopoldVonBuschLight May 30 '17 at 21:42

0 Answers0