What will be the lifetime of temporary instance?

Question

class A
{
public:
    A()
    {

    }
    A(A &copy)
    {

    }
};
void foo(A a)
{

}
int main()
{
    foo(A());
}

Will the temporary instance generated by calling A() be deleted after the copy constructor has ended or after the function foo has ended?

As it stands, the code will not compile - the signature of the copy constructor needs to be `A(const A &copy)`. — , May 26 '17 at 15:22
@NeilButterworth: You're correct although some compilers allow it as an extension. — Bathsheba, May 26 '17 at 15:22

score 3 · Accepted Answer · answered May 26 '17 at 15:21

3

The temporary is destroyed at the end of the full-expression. That means after foo has returned.

A full-expression is an expression that is not a subexpression of another expression.

answered May 26 '17 at 15:21

eerorika

1 Answers1