use .append more than once?

Question

Is there a quicker way to write .append more than once? Like:

    combo.append(x) * 2

Instead of:

    combo.append(x)
    combo.append(x)

I know you cant multiply it by 2, so I'm wondering if there is a faster way?

You can select just *one* of the answers, not both. :-) Pick the one that *you* feel helped you the most. Not picking any is a valid choice too. — Martijn Pieters, May 21 '17 at 18:15

score 1 · Answer 1 · edited May 23 '17 at 12:18

1

You can extend instead of append:

combo.extend([x] * 2)

If combo is a local or a global, you can also use += to extend a list:

combo += [x] * 2

If combo is an class attribute, just be careful if you are referencing it on an instance, see Why does += behave unexpectedly on lists?

edited May 23 '17 at 12:18

Community

answered May 20 '17 at 17:00

Martijn Pieters

score 1 · Accepted Answer · answered May 20 '17 at 17:00

1

You might try something like combo.extend([x]*t) to append t copies of x.

answered May 20 '17 at 17:00

Horia Coman

2 Answers2