Check if one element exists in an array of objects

Question

I have the following array of objects:

var memberships = [
  {
    id: 1,
    type: 'guest'
  },
  {
    id: 2,
    type: 'member'
  }
];

How can I verify if such an array has at least one element with type 'member'?

Note that the array can also have no elements.

Does this answer your question? [Check if object value exists within a Javascript array of objects and if not add a new object to array](https://stackoverflow.com/questions/22844560/check-if-object-value-exists-within-a-javascript-array-of-objects-and-if-not-add) — Yogi, Dec 24 '20 at 10:57

Dan Philip · Answer 1 · 2017-04-20T12:22:34.010

Use array.some()

var memberships = [{
    id: 1,
    type: 'guest'
  },
  {
    id: 2,
    type: 'member'
  }
];

var status = memberships.some(function(el) {
  return (el.type == 'member');
});
console.log(status);

Array.some()

Array.some() executes the callback function once for each element present in the array until it finds one where callback returns a truthy value. If such an element is found, some() immediately returns true. Otherwise, some() returns false.

Dan Cantir · Answer 2 · 2021-03-01T10:18:35.780

5

You can use Array#some method:

const memberExists = memberships.some(member => member.type === 'member');

Then, if(memberExists) ...

edited Mar 01 '21 at 10:18

answered Apr 20 '17 at 12:13

Dan Cantir

2,767
10
24

Thanks for this! Very helpful. – Sara Inés Calderón Sep 18 '18 at 19:20

Weedoze · Answer 3 · 2017-04-20T12:15:59.500

1

You can use Array#some

var memberships = [
  {
    id: 1,
    type: 'guest'
  },
  {
    id: 2,
    type: 'member'
  }
];

console.log(memberships.some(m=>m.type==='member'));

edited Apr 20 '17 at 12:15

answered Apr 20 '17 at 12:14

Weedoze

12,968
1
34
57

`Array.prototype.some()` would likely be faster/cheaper since it doesn't need to process the whole array. – David Thomas Apr 20 '17 at 12:15
@DavidThomas That's true – Weedoze Apr 20 '17 at 12:16

score 1 · Answer 4 · answered Apr 20 '17 at 12:19

1

You can also use find, which returns the first object if found else undefined.

let a = memberships.find(o => o.type === 'member');

if (a) {
  ...do something
}

answered Apr 20 '17 at 12:19

FrankCamara

348
4
9

score 1 · Accepted Answer · answered Apr 20 '17 at 12:27

1

I think this may help

let resultArray=memberships.filter(function(item) {
     return item["type"] === 'member';
});

the result array holds the data of the objects that has type member

answered Apr 20 '17 at 12:27

sravanthi

175
1
1
15

Nag Repala · Answer 6 · 2022-04-27T04:05:56.357

0

    var memberships = [
        {
            "Name": "family_name",
            "Value": "Krishna"
        },
        {
            "Name": "email",
            "Value": "harikrishnar88@gmail.com"
        }
    ];

    let resultArray=memberships.filter(function(item) {
      return item["Name"] === 'email';
});

edited Apr 27 '22 at 04:05

answered Apr 14 '21 at 09:05

Nag Repala

11
3

Check if one element exists in an array of objects

6 Answers6

Array.some()