Unix awk how to pass variable to the print statement

Question

I am trying to print the filename with the output of the command below

less $file|awk -F' ' '{print '$file' $2,$3,$5}

it prints without the variable value

x y z
a b c

I want to print

file1 x y z
file1 a b c

Answer 1

Try: awk -F' ' '{print FILENAME " " $2 " " $3 " " $5}' $file

FILENAME is a built-in variable of awk, representing the input filename.