remove middle octets from an ip until some criteria is met

Question

I have a string of IP and port numbers which is like : "10.213.110.49.33482;10.213.106.12.20001:" The two ip's are separated by a semi-colon. Last decimal shows port number.
What I need is to convert the above string which would look like: "10.213.110.49 20001:".
I want to remove the middle octets and port number of first IP using SHELL SCRIPT only. I want to extract the IP from first part ignoring the port number and from second IP i want the port number only

http://stackoverflow.com/questions/428109/extract-substring-in-bash — Harsha W, Mar 31 '17 at 06:57
*of first IP* - should the second IP be ignored OR the first IP must derive some parts of the second IP??? Make it more clear — RomanPerekhrest, Mar 31 '17 at 06:58
I want to extract the IP from first part ignoring the port number and from second IP i want the port number only. — Prashant Kumar, Mar 31 '17 at 07:10
What do you mean by "SHELL SCRIPT only"? You have tags for e.g. sed, so it would be OK to call sed from shell? — Yunnosch, Mar 31 '17 at 07:20
Yeah, I dont want solutions with python or any other language. I can use sed, awk, substitution or whatever I can use in a shell script @Yunnosch — Prashant Kumar, Mar 31 '17 at 07:25

perreal · Answer 1 · 2017-03-31T07:21:41.147

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using sed:

sed 's/\.[0-9]*;.*\.\([0-9]*:\)/ \1/' <<< \
         '10.213.110.49.33482;10.213.106.12.20001:'

gives:

10.213.110.49 20001:

edited Mar 31 '17 at 07:21

answered Mar 31 '17 at 07:13

perreal

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Thankyou sir @perreal. Working absolutely fine and is a good solution. Really helpful :) – Prashant Kumar Apr 05 '17 at 06:53
You don't need the back references at all, just remove that part and replace with a space – grail Apr 05 '17 at 08:26

RomanPerekhrest · Answer 2 · 2017-03-31T07:35:01.223

0

awk solution:

s="10.213.110.49.33482;10.213.106.12.20001:"
echo $s | awk -F"[.;]" '{OFS=".";print $1,$2,$3,$4" "$10}'

The output:

10.213.110.49 20001:

edited Mar 31 '17 at 07:35

answered Mar 31 '17 at 07:14

RomanPerekhrest

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Thanks a lot sir. Clever one from ur side. Really helpful :) – Prashant Kumar Apr 05 '17 at 06:52

score 0 · Answer 3 · answered Mar 31 '17 at 07:44

0

You can just use bash substitution, just takes a couple of steps:

s='10.213.110.49.33482;10.213.106.12.20001:'

port="${s##*.}"

ip="${s%;*}"
ip="${ip%.*}"

echo "$ip $port"

answered Mar 31 '17 at 07:44

grail

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Thanks a lot @grail. u did exactly what i needed. – Prashant Kumar Apr 05 '17 at 06:51
Can u please explain what you did here. – Prashant Kumar Oct 05 '17 at 06:09
# removes from the start and % removes from the end. If you double either it removes from the same direction until the last occurrence. So ${s#*.} would remove from the front up until first period, but ${s##*.} would remove all up until the last period in the string – grail Oct 05 '17 at 11:49

remove middle octets from an ip until some criteria is met

3 Answers3