Python String byte to HEX with IF condition

Question

I want to convert the byte string to hex for below variable.I want the result as DTCLogged[loopindex] = 0xDA

>>> DTCLogged[loopindex]
   'DA'

After that it should satisfy the IF condition

if (DTCLogged[loopindex] & 0xC0)

How can I do it?

`int('da', 16) == 218`, it that's what you're after. See e.g. http://stackoverflow.com/q/209513/3001761 — jonrsharpe, Mar 27 '17 at 12:04

score 0 · Accepted Answer · edited Mar 27 '17 at 12:05

0

Parse it as a hexadecimal integer:

x = int(DTCLogged[loopindex], 16) & 0xC0

edited Mar 27 '17 at 12:05

jonrsharpe

answered Mar 27 '17 at 12:04

cymruu

1 Answers1