How to print this loop result as a immediate sequence (like a single number)?

Question

This is my loop:

hi = 567
z = len(str(hi))
his = str(hi)
for i in range(z - 1, -1 ,-1):
    x = his[i],
    print x,

What I get is:

('7',) ('6',) ('5',)

Is there a way to get it like this:

Thank You!

should the result be an integer or a string? Or is printing it the important part, no matter what the type? — MSeifert, Mar 04 '17 at 21:09

Szabolcs · Answer 1 · 2017-03-04T21:34:49.157

2

Try this:

print int(str(hi)[::-1])

EDIT: Some performance benchmark compared to the reversed and join solution:

Without int conversion:

>>> timeit.timeit("str(hi)[::-1]", setup='hi=567')
0.33620285987854004
>>> timeit.timeit("''.join(reversed(str(hi)))", setup='hi=567')
0.8570940494537354

With int conversion:

>>> timeit.timeit('int(str(hi)[::-1])', setup='hi=567')
0.6945221424102783
>>> timeit.timeit("int(''.join(reversed(str(hi))))", setup='hi=567')
1.2800707817077637

edited Mar 04 '17 at 21:34

answered Mar 04 '17 at 21:07

Szabolcs

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btw: What does the `[::-1]` part do? – John Finkelstein Mar 04 '17 at 21:11
It's reversing the string. Quite handy for str operations like this :D – Szabolcs Mar 04 '17 at 21:12
strange... it worked fine, but now it prints it 3 times... – John Finkelstein Mar 04 '17 at 21:16
Prints what 3 times? – Szabolcs Mar 04 '17 at 21:17
nvm I put it in the loop (so it printed the reversed num 3 times) – John Finkelstein Mar 04 '17 at 21:18
1

@JohnFinkelstein, this goes in place of the loop, not in it. – anonymoose Mar 04 '17 at 21:35
@Szabolcs, is there a way to do it with only commas? – John Finkelstein Mar 05 '17 at 16:42
What do you mean by doing it with commas? – Szabolcs Mar 05 '17 at 16:50
When I did `print x,` i got `('7',) ('6',) ('5',)`, I used the comma to print it on the same line,,, – John Finkelstein Mar 05 '17 at 17:36
I don't really understand what are you looking for. Please provide an example input - output pair so I can help. – Szabolcs Mar 05 '17 at 18:25
Is there a way to do it in a loop with `range`? – John Finkelstein Mar 05 '17 at 18:33
Of course there is a way, but I still don't know what you want as an output. Please show an example. – Szabolcs Mar 05 '17 at 20:17
I want to get instead of `765` I want to get `567` without using any special python commands like `::-1` ,just `range` , `,` etc... – John Finkelstein Mar 05 '17 at 21:53
@Szabolcs? Are you still here? – John Finkelstein Mar 05 '17 at 22:44
@JohnFinkelstein Try this: `his = str(hi) for i in range(len(his)-1,-1,-1): print his[i],`. For `hi = 567` it will output `7 6 5`. But this solution is far from being python. – Szabolcs Mar 06 '17 at 11:05

score 1 · Answer 2 · answered Mar 04 '17 at 21:07

1

Just use ''.join and reversed:

>>> ''.join(reversed(str(hi)))
'765'

answered Mar 04 '17 at 21:07

MSeifert

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It prints it 3 times... – John Finkelstein Mar 04 '17 at 21:13
@JohnFinkelstein You don't need the loop anymore if you use that solution. :) – MSeifert Mar 04 '17 at 21:15
@MSeifet Is there a way to use `x` instead of the `reversed`? Like: `''.join(x(str(hi)))`? – John Finkelstein Mar 05 '17 at 23:35
@JohnFinkelstein I don't understand. What's wrong about `reversed`? What should be `x`? – MSeifert Mar 06 '17 at 11:40

score 0 · Answer 3 · answered Mar 04 '17 at 21:06

0

you have an extra comma on the 5th line. change your code to this

hi = 567
z = len(str(hi))
his = str(hi)
for i in range(z - 1, -1 ,-1):
    x = his[i]
    print x,

answered Mar 04 '17 at 21:06

DorElias

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How to print this loop result as a immediate sequence (like a single number)?

3 Answers3