python remove elements from list based on other list

Question

I'm stuck with a part in one of my codes where I have to delete all the occurances present in listA that are identical in listB.

Example:

A=[1,4,4,4,3,3,2,1,5,5]
B=[4,3]

Result should be A=[1,2,1,5,5]. Ideally I would want to do it in linear time.

sorry, theres a minor change in my question now. i would want my list A to have repeated values too — Sai Pardhu, Feb 23 '17 at 19:42

Mithilesh Gupta · Answer 1 · 2017-02-23T07:47:06.220

1

using Set Operations:

list(set(A) - set(B))

Using List Comprehension

list(set([i for i in A if i not in B]))

edited Feb 23 '17 at 07:47

answered Feb 23 '17 at 07:17

Mithilesh Gupta

Still there is a chance for duplicate elements, – Rahul K P Feb 23 '17 at 07:45
sorry, theres a minor change in my question now. i would want my list A to have repeated values too – Sai Pardhu Feb 23 '17 at 19:41

Rahul K P · Accepted Answer · 2017-02-23T19:45:44.887

0

Try with list comprehension,

In [11]: [i for i in A if i not in B]
Out[11]: [1, 2, 1, 5, 5]

edited Feb 23 '17 at 19:45

answered Feb 23 '17 at 07:17

Rahul K P

sorry, theres a minor change in my question now. i would want my list A to have repeated values to – Sai Pardhu Feb 23 '17 at 19:41
@SaiPardhu Changed accordingly – Rahul K P Feb 23 '17 at 19:45
1

awesome, got it thanks!! – Sai Pardhu Feb 23 '17 at 19:55

2 Answers2