How to add title to seaborn boxplot

Question

Seems pretty Googleable but haven't been able to find something online that works.

I've tried both sns.boxplot('Day', 'Count', data= gg).title('lalala') and sns.boxplot('Day', 'Count', data= gg).suptitle('lalala'). None worked. I think it might be because I'm also working with matplotlib.

score 298 · Answer 1 · answered Feb 23 '17 at 07:47

298

Seaborn box plot returns a matplotlib axes instance. Unlike pyplot itself, which has a method plt.title(), the corresponding argument for an axes is ax.set_title(). Therefore you need to call

sns.boxplot('Day', 'Count', data= gg).set_title('lalala')

A complete example would be:

import seaborn as sns
import matplotlib.pyplot as plt

tips = sns.load_dataset("tips")
sns.boxplot(x=tips["total_bill"]).set_title("LaLaLa")

plt.show()

Of course you could also use the returned axes instance to make it more readable:

ax = sns.boxplot('Day', 'Count', data= gg)
ax.set_title('lalala')
ax.set_ylabel('lololo')

answered Feb 23 '17 at 07:47

ImportanceOfBeingErnest

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its a shame `set_title()` and similar functions do not `return self`, that would be neat. – Laurens Koppenol Aug 29 '19 at 11:33
@LaurensKoppenol Matplotlib's credo is to return the object that the method creates or manipulates. This is a question of flexibility; and matplotlib explicitely wants to give users this flexibility. More high-level APIs that sit on top of matplotlib often decide to allow for chaining, but in those cases you have problems manipulating the underlying objects when wanting some non-standard behaviour. – ImportanceOfBeingErnest Aug 29 '19 at 11:41
when combining the various interfaces matplotlib has I definitely agree – Laurens Koppenol Aug 29 '19 at 11:45
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AttributeError: 'FacetGrid' object has no attribute 'set_title' – Dumb ML Aug 20 '20 at 15:04

score 59 · Answer 2 · edited Aug 14 '20 at 04:06

59

sns.boxplot() function returns Axes(matplotlib.axes.Axes) object. please refer the documentation you can add title using 'set' method as below:

sns.boxplot('Day', 'Count', data=gg).set(title='lalala')

you can also add other parameters like xlabel, ylabel to the set method.

sns.boxplot('Day', 'Count', data=gg).set(title='lalala', xlabel='its x_label', ylabel='its y_label')

There are some other methods as mentioned in the matplotlib.axes.Axes documentaion to add tile, legend and labels.

edited Aug 14 '20 at 04:06

Rémy Hosseinkhan Boucher

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answered Feb 06 '20 at 06:29

akhil penta

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This is a nice solution since it also works for `sns.relplot()`. – James Brusey Oct 08 '20 at 10:43

score 41 · Answer 3 · answered Feb 23 '17 at 06:27

41

Try adding this at the end of your code:

import matplotlib.pyplot as plt

plt.title('add title here')

answered Feb 23 '17 at 06:27

Stefano Potter

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perhaps the best solution, sure not purely sns -ish, but hustle free and simple. Thanks – data_runner Nov 10 '21 at 20:37

score 16 · Answer 4 · answered May 26 '20 at 17:20

For a single boxplot:

import seaborn as sb
sb.boxplot(data=Array).set_title('Title')

For more boxplot in the same plot:

import seaborn as sb
sb.boxplot(data=ArrayofArray).set_title('Title')

e.g.

import seaborn as sb
myarray=[78.195229, 59.104538, 19.884109, 25.941648, 72.234825, 82.313911]
sb.boxplot(data=myarray).set_title('myTitle')

score 7 · Answer 5 · answered Mar 24 '20 at 15:47

7

.set_title('') can be used to add title to Seaborn Plot

import seaborn as sb
sb.boxplot().set_title('Title')

answered Mar 24 '20 at 15:47

Kranthi

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How to add title to seaborn boxplot

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