Concise way to fill up an ArrayList with data

Question

I need to fill an ArrayList with some (random) data. I wonder if Java 8/9 allows a more concise way than this:

List list = new ArrayList();
for (int ii=0;ii<100;ii++)
list.add(UUID.randomUUID().toString());

Thanks!

Is this what you're looking for ? http://stackoverflow.com/questions/33140535/java-8-fill-arraylist — DamCx, Feb 16 '17 at 09:25

score 6 · Accepted Answer · answered Feb 16 '17 at 09:27

6

Probably this will do:

Supplier<String> supplier = () -> UUID.randomUUID().toString();
List<String> list = Stream.generate(supplier).limit(100).collect(Collectors.toList());

answered Feb 16 '17 at 09:27

Konstantin Yovkov

60,548
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Ironically, the old-fashioned approach from the question is way shorter than your answer (96 vs. 151 chars, including linefeeds), but that's not your fault ;-) – Erich Kitzmueller Feb 16 '17 at 09:32
There are so many possibilities yeah this is another one but not concise :P – Suresh Atta Feb 16 '17 at 09:33
2

To make it shorter, you don't have to create a `supplier`-variable. You could just put the lambda-function as argument into `generate` – Thomas Böhm Feb 16 '17 at 09:35
Code golf shows us that Java was not really intended to be concise ;) – AxelH Feb 16 '17 at 09:40
Thanks for the reply. Yes not more concise, however I've learnt something new though! – Carla Feb 16 '17 at 09:40

Concise way to fill up an ArrayList with data

1 Answers1