Parse error: syntax error, unexpected '!'

Question

i am getting following error while running the code
any help

if(!$subcurpass){
        $form->setError($field, "* Current Password not entered");
     }
     else{
        $subcurpass = stripslashes($subcurpass);
        if(strlen($subcurpass) < 4   
        !eregi("^([0-9a-z])+$", ($subcurpass = trim($subcurpass)))){
           $form->setError($field, "* Current Password incorrect");

i dont know i missed or not coz its a very big code :( php version 5.6.29 — waleed khan, Feb 10 '17 at 21:44
@Andy may or may not but I'm not going to test this for them. — Funk Forty Niner, Feb 10 '17 at 21:47
@Fred-ii-: Was that directed at me? If so, what did I do/not do? — AbraCadaver, Feb 10 '17 at 22:01
@AbraCadaver Sorry, I'm not following. However, nothing was aimed at you. — Funk Forty Niner, Feb 10 '17 at 22:02
@Fred-ii- _get in the habit of properly closing questions_ Maybe a comment was deleted before that. — AbraCadaver, Feb 10 '17 at 22:46
@AbraCadaver OOoohhh, "that". No, that was for the OP. They haven't (marked as) closed any of their questions with solutions given. Plus, I would have pinged "you" had it been aimed at you ;-) — Funk Forty Niner, Feb 10 '17 at 23:06

Andy · Answer 1 · 2017-02-10T21:48:18.370

0

In your if condition below, you are checking the length of a string and then also doing a regular expression match on the string. Those are two separate logic operations and you need to join them together with either an OR (||) or an AND (&&) depending on what you're trying to achieve:

if(strlen($subcurpass) < 4   
    !eregi("^([0-9a-z])+$", ($subcurpass = trim($subcurpass))))

You're missing a logic operator after

if(strlen($subcurpass) < 4

edited Feb 10 '17 at 21:48

answered Feb 10 '17 at 21:39

Andy

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can you explain please – waleed khan Feb 10 '17 at 21:44
thanks for your help dude...i will read whole code again and try to alter the code – waleed khan Feb 10 '17 at 21:52

Parse error: syntax error, unexpected '!'

1 Answers1