How to get date("Y-m-d") from date("Y-m-d H:i:s")?

Question

how can I get and store date('2017-02-02') in php variable from result : datetime("2017-02-02 17:02:03").

Then you can select the date with the mysql function `DATE` (see https://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html) - or use `strotime()` in PHP, use `DateTime` objects.. May ways to go about this. — Qirel, Feb 08 '17 at 11:09
All you need to know is right here: http://php.net/manual/en/function.date.php — PhpDude, Feb 08 '17 at 11:26

beta-developper · Accepted Answer · 2017-02-08T11:16:43.053

5

Do you mean getting 2017-02-02 from 2017-02-02 17:02:03, well you have many options,

$date = date('Y-m-d', strtotime('2017-02-02 17:02:03'));

OR

list($date) = explode(" ", '2017-02-02 17:02:03');

OR

    $arr = explode(" ", '2017-02-02 17:02:03');
    $date = array_shift($arr);

OR

 $dateObj = DateTime::createFromFormat("Y-m-d H:i:s", '2017-02-02 17:02:03');
 $date = $dateObj->format("Y-m-d");

edited Feb 08 '17 at 11:16

answered Feb 08 '17 at 11:09

beta-developper

score 1 · Answer 2 · answered Feb 08 '17 at 11:07

1

You need to convert the date to a timestamp with strtotime()

Example:

<?php
echo date("Y-m-d", strtotime('2017-02-02 17:02:03'));
?>

I hope this will help you!

answered Feb 08 '17 at 11:07

node_modules

2 Answers2