Java/android how to start an AsyncTask after 3 seconds of delay?

Question

How can an AsyncTask be started after a 3 second delay?

How important is it that the task persist through app restarts? — Mooing Duck, Nov 08 '17 at 01:13

Facundo Olano · Answer 1 · 2016-08-04T14:30:47.563

18

Using handlers as suggested in the other answers, the actual code is:

new Handler().postDelayed(new Runnable() {
    @Override
    public void run() {
        new MyAsyncTask().execute();
    }
}, 3000);

edited Aug 04 '16 at 14:30

answered Nov 24 '15 at 18:50

Facundo Olano

2,402
2
25
32

score 17 · Accepted Answer · edited May 28 '13 at 17:07

17

You can use Handler for that. Use postDelayed(Runnable, long) for that.

Handler#postDelayed(Runnable, Long)

edited May 28 '13 at 17:07

saiyancoder

1,237
1
13
20

answered Nov 14 '10 at 12:38

Juhani

5,008
5
31
34

score 13 · Answer 3 · answered Apr 14 '14 at 10:35

13

You can use this piece of code to run after a 3 sec delay.

new Timer().schedule(new TimerTask() {          
    @Override
    public void run() {

        // run AsyncTask here.    


    }
}, 3000);

answered Apr 14 '14 at 10:35

mani

3,226
2
28
35

what if after 1sec application is closed? i mean the application is completely destroyed? will this timer still run after 3 sec... i am asking bcz my need is to run AsyncTask even if the app is closed.... – kumar Apr 20 '16 at 14:31
No, it will not run. If you need to persist through app restarts, use alarms. – Mooing Duck Nov 08 '17 at 01:13

score 4 · Answer 4 · answered Nov 14 '10 at 12:40

4

Use Handler class, and define Runnable handleMyAsyncTask that will contain code executed after 3000 msec delay:

mHandler.postDelayed(handleMyAsyncTask, 1000*3);

answered Nov 14 '10 at 12:40

Zelimir

10,918
5
47
45

score 0 · Answer 5 · answered Jun 26 '20 at 14:41

Use CountDownTimer.

  new CountDownTimer(3000, 1000) {

        public void onTick(long millisUntilFinished) {

           //do task which continuously updates

        }

        public void onFinish() {

           //Do your task
         
        }

    }.start();

3000 is total seconds and 1000 is timer tick on that time means on above case timer ticks 3 time.

Java/android how to start an AsyncTask after 3 seconds of delay?

5 Answers5

Linked