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I can't find info does golang depend on c runtime? If it's depend on it is it's statically compiled in go-binary to make Go-app work everywhere without dependences?

Here is topic about what C-runtime is

kostix
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Dmitry Bubnenkov
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2 Answers2

17

If you're talking about executable files provided by a Go compiler, then the answer is "yes or no—it depends":

In most cases, the resulting executable program does not depend on a C run-time library.

However, on some platforms under certain circumstances the C runtime library gets dynamically linked in. In particular, this was the case with Go versions < 1.5 on Linux when DNS resolution was used: the runtime depended on the platform's libc implementation to handle such resolution. In 1.5 this has been reworked.

Another possible case is (IIRC) Solaris which provides no stable way to access the kernel's syscalls directly and requires routing these calls through the platform's libc.

There is another case: using cgo which is a layer to interface Go code with foreign C code. Using cgo makes your Go program depend on the C runtime. Note that you might not use cgo directly but one or more of the third-party packages you might be using can use cgo, and—transitively—your program ends up depending on the C runtime library.

Scott Stensland
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kostix
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    The [cgo documentation](https://golang.org/cmd/cgo/) says that cgo is enabled by default for native builds. So, it looks like one has to set CGO_ENABLED=0 to make sure that there is no a dependency on C runtime. – SergiyKolesnikov Aug 19 '20 at 15:53
6

I think the accepted answer is correct, but a binary which imports the 'net' package usually depends on a c runtime even in go 1.10 and Unix.

Here is the example of the simple echo server:

package main

import (
        "io"
        "log"
        "net"
)

func main() {
        ln, err := net.Listen("tcp", ":8080")
        if err != nil {
                log.Fatal(err)
        }

        for {
                conn, err := ln.Accept()
                if err != nil {
                        log.Print(err)
                        continue
                }

                _, err = io.Copy(conn, conn) // blocked until the client closes the conn.
                if err != nil {
                        log.Print(err)
                        continue
                }

                if err = conn.Close(); err != nil {
                        log.Print(err)
                }
        }
}

Build it and check its dependencies:

$ go build ./libc_check.go
$ ldd ./libc_check
        linux-vdso.so.1 =>  (0x00007ffe34fc1000)
        libpthread.so.0 => /lib/x86_64-linux-gnu/libpthread.so.0 (0x00007fc005d4e000)
        libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007fc005984000)
        /lib64/ld-linux-x86-64.so.2 (0x00007fc005f6b000)

It is because 'the decision of how to run the resolver applies at run time, not build time' as the release note indicates.

To avoid this dependency, use the 'netgo' build tag like this:

$ go build -tags netgo ./libc_check.go
$ ldd ./libc_check
        not a dynamic executable
yagami kishin
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  • Don't know which version of Go you used, but on 1.11.1 your example produces binary without any dependencies – creker Dec 28 '18 at 14:32
  • Ummm, today I checked my example with 1.11.1 and 1.11.4 on Linux, but the binary still depends on c runtime. I also checked it using the `golang:1.11.1` docker image. So I'm not really sure why the example doesn't work in your env. – yagami kishin Dec 31 '18 at 09:11
  • try building with cgo turned off. I tested by cross-compiling on Windows and macOS. The binary had an empty dynamic section. – creker Dec 31 '18 at 11:05