GREP - Exclude line entries that have a question mark "?"

Question

I have a large file with over 800k entries (access log file). I need to output a file with only clean URLs (without parameters / "?") in the URL.

Output should only display entries that DON'T have a "?" in the URL.

Parameter url:

http://www.example.com/sample?parameter=1

Also related: http://stackoverflow.com/questions/4373675/how-to-invert-a-grep-expression — l'L'l, Jan 09 '17 at 10:58
Excellent closing guys. Have any of you actually tried a regex with a question mark in grep? — Derf Skren, Jan 14 '20 at 22:17

Inian · Answer 1 · 2017-01-09T19:45:04.113

4

In POSIX grep with the flag -v for inverse match,

grep -v "?" file

Or using awk with !

awk '!/?/' file

Using GNU sed

sed -n '/?/!p' file

edited Jan 09 '17 at 19:45

answered Jan 09 '17 at 10:52

Inian

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There's nothing GNU specific about grep -v. – Ed Morton Jan 09 '17 at 19:43

score 3 · Answer 2 · answered Jan 09 '17 at 10:52

@Seasonal_showers: You haven't shown us a handful samples, so considering that your Input_file will have only URLs and nothing else, could you please try following then.

grep -v '?' Input_file

Let me know if this is not helping, you could show more sample Input_file details for better understanding then.

GREP - Exclude line entries that have a question mark "?"

2 Answers2