Triple equal operator fails when checking for one of variants but they are the same type

Question

$type = 'bravo';

if ($type === ('alpha' || 'bravo')) {
    echo $type;
}

This never returns anything. Why this is happening?

The subexpression `('alpha' || 'bravo')` evaluates to `True`. — mario, Jan 05 '17 at 13:10

score 2 · Answer 1 · answered Jan 05 '17 at 13:09

2

Try this:

if ($type === 'alpha' || $type === 'bravo') {
    echo $type;
}

You have to check values individually.

answered Jan 05 '17 at 13:09

Mayank Pandeyz

score 1 · Answer 2 · answered Jan 05 '17 at 13:10

1

'alpha' || 'bravo' is boolean true not string 'bravo'

answered Jan 05 '17 at 13:10

LF00

2 Answers2