What does & mean after a function declaration

Asked Jan 03 '17 at 01:48

Active Jan 03 '17 at 01:48

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I encountered a some syntax I've never seen before when searching for another answer. One particular function was typed as:

Foo& operator=(Foo&&) &; // <-- ???

I have no idea what the & symbol after the declaration does to this statement. When I typed it into my IDE, it compiled fine without any errors or warnings, so this is valid.

Note: My attempts at searching this question just yield people asking about references in the return or parameters

asked Jan 03 '17 at 01:48

James Nguyen

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*"Note: My attempts at searching this question just yield people asking about references in the return or parameters"* Well, it was not *trivial* to research, I had to go to the second page of google results. ;) – Baum mit Augen Jan 03 '17 at 01:55
@BaummitAugen ¯\_(ツ)_/¯ thanks anyway – James Nguyen Jan 03 '17 at 01:55
Please remember the purpose of the site is to share answers. You may have found the answers, but other people may not. – Andy Ibanez Jan 03 '17 at 01:58
@AndyIbanez I'm not sure I understand the purpose of this comment. Who is it even addressed at? – Baum mit Augen Jan 03 '17 at 02:02
Both of you, but it got closed for being a duplicate anyway. – Andy Ibanez Jan 03 '17 at 02:03

What does & mean after a function declaration

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