regExp: get everything between opening bracket '(' and closing bracket ')'

Question

I have following regular Expression: /prefix(([^)]+))/g

This expression matches everything between 'prefix(' and ')'.

For example:

value = 'prefix(foo) bar(foo)';

return value.match( /prefix\(([^)]+)\)/g )

result: 'prefix(foo)'

What I am trying to achieve is this:

value = 'prefix() bar(foo)';

return value.match( correctRegularExpression )

result: 'prefix()'

I am searching for correctRegularExpression and I am really stuck here since I am new to regular Expressions.

Or `return value.match(/prefix\(.*?\)/g)`. It looks like what is inside the parentheses is not used, so there is no need using the capturing group. — Wiktor Stribiżew, Dec 29 '16 at 13:28

score 0 · Answer 1 · answered Dec 29 '16 at 13:35

Use capture groups in your regex like so:

var value = 'prefix(hello) foo(goodbye)';

var matches = value.match(/prefix\((\w*)\)/);

console.log(matches[1]);

1 Answers1