Why division is always ZERO?

Question

int value = 10 * (50 / 100);

The expected answer is 5, but it is always zero. Could anyone please give me detail explanation why it is?

Thanks much in advance.

(50 / 100) is evaluated first, and the result of an integer division discards the fraction part. — Steeve, Dec 22 '16 at 08:18
`5` is an int, but the result of `50/100` isn't `5`, it's `0.5`. Which is not an int. So instead you get 0, since 100 fits exactly 0 times into 50. — Nyerguds, Dec 22 '16 at 09:07

Mihai Alexandru-Ionut · Answer 1 · 2016-12-22T08:27:33.613

3

Because the result of 50/100 is 0 .

50/100 is equals to int(50/100) which returns 0.

Also, if you want to return 5, use this:

int value = (int)(10 * (50 / 100.0));

The result of (50/100.0) is 0.5.

edited Dec 22 '16 at 08:27

answered Dec 22 '16 at 08:18

Jeroen van Langen · Answer 2 · 2016-12-22T08:24:35.227

2

Because you're doing an integer division: (50 / 100) gives 0

Try this:

int value = (int)(10 * (50 / 100.0));

Or reverse the multiply/division

int value = (10 * 50) / 100;

So it's getting multiplied before the divide

edited Dec 22 '16 at 08:24

answered Dec 22 '16 at 08:18

Jeroen van Langen

emish89 · Answer 3 · 2016-12-22T09:02:15.093

1

You make operation on int values. 50/100 in int is 0.

edited Dec 22 '16 at 09:02

answered Dec 22 '16 at 08:18

emish89

3 Answers3