Continue on exception and go to next statement python

Question

Lets say I have a big block of code and whenever I hit an exception I want to ignore it and proceed to next line. Is that possible in python? I want something like-

try:
   #some code here
   #see an exception, ignore, continue to next line
   #more code
   #any more code , ignore and march on through rest of block
except:
   pass

yeah: wrap a `try/except` around every line. But it's not very useful... say if a line defines `a` and you get an exception there, `a` is not defined. next line uses `a`: you get an exception again... and so on. — Jean-François Fabre, Dec 15 '16 at 16:00
What's *in* that big block of code? Just steamrolling over the errors seems likely to lead to more problems than it solves. But there's always [`fuckit`](https://github.com/ajalt/fuckitpy). — jonrsharpe, Dec 15 '16 at 16:08
I am using Python 2. I thought of wrapping try/except but is there any other way — Illusionist, Dec 15 '16 at 16:09
@OP please give some context, *why* is that a think you think you want to do? — jonrsharpe, Dec 15 '16 at 16:11
I just want to know if it can be done and thanks for the link lol. Ive sometimes come across buggy code and I want to run it and see how badly broken it is before fixing it. — Illusionist, Dec 15 '16 at 16:34

score 0 · Answer 1 · answered Dec 15 '16 at 16:01

Yes, you can do it in this way, the try-except must around each line, once the line throws exception, it will go to the exception statement and then go to next line. You'd better print/log the exception line.

for line in inputs:
    try:
        # your code here
    except Exception as e:
        # log your exception here

Continue on exception and go to next statement python

1 Answers1