How to apply regex to check route param is in array

Question

I have route like this. I am trying to check if route param social is either facebook, google or twitter.

Route::get('/login/{social}', 'Auth\LoginController@loginSocial')
->where('social',["facebbok","google","twitter"]);

Above route is not working. It asks for regex. Please help.

How to check this ?

Answer is here. Previously i solved my problem with it. http://stackoverflow.com/a/3809435/4582992 — kemal akoğlu, Dec 12 '16 at 11:36
Previously i solved my problem with this link. Hope you too http://stackoverflow.com/a/3809435/4582992 — kemal akoğlu, Dec 12 '16 at 11:37

score 3 · Accepted Answer · answered Dec 12 '16 at 11:37

3

Try this:

Route::get('/login/{social}', 'Auth\LoginController@loginSocial')
->where('social','(facebook|google|twitter)');

answered Dec 12 '16 at 11:37

Mustofa Rizwan

score 0 · Answer 2 · answered Dec 12 '16 at 11:38

The where method on a route instance accepts the name of the parameter and a regular expression, your second parameter isn't a regular expression:

Route::get('/login/{social}', 'Auth\LoginController@loginSocial')
->where('social','(facebook|google|twitter)');

Here is a valid RegExp

score 0 · Answer 3 · answered Dec 12 '16 at 11:39

0

You haven't stated what the method signature of the ->where but at a guess:

Route::get('/login/{social}', 'Auth\LoginController@loginSocial')
->where('social', "/^(facebook|google|twitter)$/i");

answered Dec 12 '16 at 11:39

John Joseph

score 0 · Answer 4 · edited Dec 12 '16 at 13:47

0

Hope this condition will helpful for you.

Route::get('/login/{social}','Auth\LoginController@loginSocial')
    ->where('social', 'facebook|google|twitter');

edited Dec 12 '16 at 13:47

Petter Friberg

answered Dec 12 '16 at 12:08

Soniya Basireddy

4 Answers4