Python error (list index out of range)

Question

I am having an issue with the following section of Python code:

def main():
file_name = sys.argv[1]
file = open(file_name, 'r')
l = []
for line in file:
    if (len(l) == 4):
        res = valid_data(l)
        if (res == False):
            print("The Data is InValid")
        else:
            print_data(l)
        l = []
    else:
        l.append(line.strip())
if (l != []):
    res = valid_data(l)
    if (res == False):
        print("The Data is InValid")
    else:
        print_data(l)
main()

Specifically, the error is as follows:

 Traceback (most recent call last):


File "C:\Users\Desktop\44.py", line 194, in <module>
main()



 File "C:\Users\Desktop\44.py", line 173, in main
information = sys.argv[1]
IndexError: list index out of range

The sys.argv might require an argument at the command line when running the script, but I'm not sure what the issue might be!

"*The sys.argv might require an argument at the command line when running the script*": it might. How are you running your program? — Andras Deak -- Слава Україні, Nov 27 '16 at 22:05
Make sure what are you expecting by `file_name = sys.argv[1]`. — Ruhul Amin, Nov 27 '16 at 22:07

score -1 · Answer 1 · answered Nov 27 '16 at 22:08

-1

sys.argv[1] is the first command line argument. Call the script like

python3 myscript.py myargument

answered Nov 27 '16 at 22:08

jmd_dk

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Python error (list index out of range)

1 Answers1