How to group a list into inclusive sequential n-length sublists?

Question

To be more precise:

A = [1, 2, 3, 4, 5, 6, 7]
def group_me(A, 4):
    # magic goes here

---> [1,2,3,4], [2,3,4,5], [3,4,5,6], [4,5,6,7]

Any ideas?

Answer 1

Try this:

def group_me(array,length):
    return [array[n:n+length] for n in range(0,len(array)-length+1)]

Answer 2

Using list comprehension

def group_me(A, n):
    return [A[i:i+n] for i in range(len(A)-n+1)]


>>> group_me([1, 2, 3, 4, 5, 6, 7], 4)
[1,2,3,4], [2,3,4,5], [3,4,5,6], [4,5,6,7]