C++: how to add int to current string in C++?

Question

Possible Duplicate:
C++ concatenate string and int

Hi,

In C# I can write like this:

int i = 0;
string text = "out.jpg";
while(true)
{
     i++;
     Object.write(i+text, stream);
}

But this is not true for C++. the problem is at: i + default.

How could I fix this in C++?

Thanks in advance. Your help is much appreciated!

Hi all, I just tried this and it works perfectly: int i = 0;char text[] = "ok";sprintf(text, "hello %d ok.jpg", i); Object.write(text, stream); Thanks! — olidev, Oct 27 '10 at 14:02

cHao · Accepted Answer · 2010-10-27T23:07:47.203

3

You could use a stringstream...

std::stringstream ss;
ss << i << text;
Object.write(ss.str(), stream);

edited Oct 27 '10 at 23:07

answered Oct 27 '10 at 13:53

cHao

+1. First I thought about `sprintf()`, but this is not really a C++ solution, rather a C one and it requires some usage of a `char` array. Using `stringstream` is probably the best solution. – rhino Oct 27 '10 at 13:56

score 1 · Answer 2 · answered Oct 27 '10 at 13:50

1

default is a keyword in C++. You can't have string default in C++. And I don't see what you are trying to achieve. Please clarify

answered Oct 27 '10 at 13:50

Armen Tsirunyan

score 1 · Answer 3 · answered Oct 27 '10 at 13:52

1

boost::format("%1%%2%") % i % default_;

answered Oct 27 '10 at 13:52

DaVinci

score 0 · Answer 4 · answered Oct 27 '10 at 13:57

0

default is a reserved keyword. Change the variable name to defaultStr or similar, and everything should work fine.

answered Oct 27 '10 at 13:57

Olie

4 Answers4