How to print an unsigned long int with printf in C?

Question

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How to printf “unsigned long” in C?

I have my number like so...

int unsigned long number = 600851475143;

I am trying to print it with printf(). Every time I try, I get a warning by the compiler.

I've tried %uld, %ld and Googling hasn't seemed to find me the answer.

I'm learning C, but have not had to use a long int before, so I'm not sure what I should be using.

What is the specifier I am chasing?

you can read this http://en.cppreference.com/w/cpp/io/c/fprintf — 王奕然, Dec 27 '16 at 04:34

score 34 · Accepted Answer · answered Oct 27 '10 at 12:16

34

I recommend using standard order (i.e. unsigned long int). %lu is the format tag you're looking for.

printf("%lu", 5ul);

answered Oct 27 '10 at 12:16

eq-

1

Sorry, I didn't know there was a conventional order. Thanks for letting me know. – alex Oct 27 '10 at 12:17

score 10 · Answer 2 · edited Jan 08 '15 at 03:57

10

int unsigned long number = 600851475143LU;
printf( "%lu", number );

prints 600851475143

edited Jan 08 '15 at 03:57

alex

answered Oct 27 '10 at 12:20

Kiril Kirov

don't forget to add `L` to end of that integer. – Matt Joiner Oct 27 '10 at 12:43
Argh, yep.. Thanks for the remark. I just copied it from the posted question. – Kiril Kirov Oct 27 '10 at 12:45

2 Answers2