Execute shell script from scala application

Question

I want to execute the sh file from Scala application. Let's say I have createPassword.sh file and I need to invoke this sh file from Scala application and get the output back.

How can I achieve through scala application?

Raphael Roth · Accepted Answer · 2016-10-19T13:31:26.570

12

This should do the trick if the script is in the current working directory (otherwise specify the full path of the script)

import sys.process._
val result = "./createPassword.sh" !!

result is then a String containing the standard output (and standard error)

EDIT: If you want to use ProcessBuillder from Java SE7, you can also use this in scala:

  import java.io.{BufferedReader, InputStreamReader}

  val p = new ProcessBuilder("/bin/bash","createPassword.sh")
  val p2 = p.start()
  val br = new BufferedReader(new InputStreamReader(p2.getInputStream()))

  var line:String = ""
  while ({line = br.readLine();  line!= null}) {
    println(line)
  }

edited Oct 19 '16 at 13:31

answered Oct 19 '16 at 11:13

Raphael Roth

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1

probably should be `"./createPassword.sh" !!` – Tzach Zohar Oct 19 '16 at 11:16
Thats true, But i neeed uses sys.process and it should not block, once the result is available ,It should be Processed – sharath chandra Oct 19 '16 at 12:28
May be similar to usage of run method under process builder – sharath chandra Oct 19 '16 at 12:49
@sharathchandra If you have an idea on how to do it in Java with ProcessBuilder, then just do it the same way in scala (you can also use ProcessBuilder from scala sourcecode) – Raphael Roth Oct 19 '16 at 13:18
1

@sharathchandra I added an example with ProcessBuilder – Raphael Roth Oct 19 '16 at 13:31

score 0 · Answer 2 · answered May 09 '19 at 21:50

0

Given your dir has a script,

`val path = "./src/test/tests/Integration/"`

`val output = Process("sh test.sh", new File("path")).!!`

answered May 09 '19 at 21:50

dedpo

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Execute shell script from scala application

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