I am trying the following:
s = "Text text text [123] ['text']"
This is my function:
def getFromSquareBrackets(s):
m = re.findall(r"\[([A-Za-z0-9_']+)\]", s)
return m
But I am obtaining:
['123', "'text'"]
I want to obtain:
['123', 'text']
How can I ignore the single quotes?
You can make ' optional using ? as
>>> re.findall(r"\['?([^'\]]+)'?\]", s)
['123', 'text']
\['? Matches [ or ['.
([^'\]]+) Matches anything other than ' or ] and captures them.
'?\] Matches ] or ']
Make ' optional and outside the capturing group
m = re.findall(r"\['?([A-Za-z0-9_]+)'?\]", s)
