Can anybody explain me why the following part of code produces the result 21? Here is the code:
int a[2][4]={3,6,9,12,15,18,21,24};
cout << 2[1[a]];
Thanks in advance!
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Using the dupe's answer, `2[1[a]]` is `*(2 + *(1+a))`. Then `*(1+a)` is `a[1]`, which is the second set of four elements. Applying the same logic to the outer part gives us the third element of that second set. – chris Aug 06 '16 at 15:46
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Great explanation! Thanks :) – gdaras Aug 06 '16 at 15:58