How to implement grep in bash scripting?

Question

I am working on to search a string on files using grep in a directory(in for loop)

for file in .* *; do 
    if [[ -f "$file" && `grep -r "$pattern" "$file"` ]]; then
    path=`pwd`/"$file"
    echo "$path"
    fi
done

ok and are you getting error or no result etc? Take your time to present your question to get quick response. — SMA, Jul 30 '16 at 18:50
missing a closing `fi;` and a closing `done;`, in that order. — J. Allan, Jul 30 '16 at 18:51
Also what if the string occurs more than once, ie in different files? — Мона_Сах, Jul 31 '16 at 03:32
Adding `-r` to `grep` when you only apply it to a file is unnecessary; the `-r` only has an effect when a directory is given as an argument to `grep`. But why not let `grep` do the job? — Jonathan Leffler, Jul 31 '16 at 04:34

score 2 · Answer 1 · edited Jul 31 '16 at 04:33

2

Avoid the for loop and use something like

grep -l "${pattern}" ${PWD}/.* ${PWD}/*

or better

find ${PWD} -type f -exec grep -l "${pattern}" {} +

edited Jul 31 '16 at 04:33

Jonathan Leffler

answered Jul 30 '16 at 19:12

Walter A

sterin jacob · Answer 2 · 2016-08-01T08:45:16.783

1

Use find command . To search in current folder

find . -exec grep "$pattern" {} \; -print'

To search in specific folder

find /home/hduser  -exec grep "$pattern" {} \; -print'

edited Aug 01 '16 at 08:45

answered Jul 31 '16 at 06:15

sterin jacob

2 Answers2