Java regex Pattern matches doesn't recognise "Escape +"

Question

I was trying the pattern ^\\+[0-9]+ to match +852(2)78911, but it seems that

Pattern.matches("^\\+[0-9]+", s)

is returning false. When I tried it in regexr it is working fine i.e. giving me a match. Am I not escaping this correctly in Java sense?

How come it works at regexpr if your pattern does not match parentheses? What result do you expect? I am sure you just need to use `Matcher#find()`. — Wiktor Stribiżew, Jul 28 '16 at 11:11

score 0 · Answer 1 · edited Jul 28 '16 at 11:13

0

Try this regex instead: ^\\+[0-9\$\$]+$

edited Jul 28 '16 at 11:13

answered Jul 28 '16 at 11:12

Jérèm Le Blond

1

You can find the formatting features here: http://stackoverflow.com/editing-help . There's no need to escape parenthesis inside a character class. Note too that when you use the `matches` method, anchors are implicit. – Casimir et Hippolyte Jul 28 '16 at 11:16

1 Answers1