Make a list of dicts by iterating over two lists (list comprehensions)

Question

The lists have the same number of elements, and the names are unique. I wonder, how can I make a dict in one action.

This is my current code:

    fees = [fee for fee in fees]
    names = [name for name in names]
    mdict = [
        {'fees': fee[i], 'names': names[i]}
        for i, val in enumerate(fees)]

Possible duplicate of [Map two lists into a dictionary in Python](http://stackoverflow.com/questions/209840/map-two-lists-into-a-dictionary-in-python) — RvdK, Jul 25 '16 at 14:10
What kind of objects are `fees` and `names` before the assignment in the first two lines? — Matt07, Jul 25 '16 at 14:13

score 3 · Accepted Answer · answered Jul 25 '16 at 14:11

3

You can use zip on both lists in a list comprehension:

mdict = [{'fees': f, 'names': n} for f, n in zip(fees, names)]

answered Jul 25 '16 at 14:11

Moses Koledoye

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score 1 · Answer 2 · answered Jul 25 '16 at 14:10

1

Try this:

result = dict(zip(fees, names))

answered Jul 25 '16 at 14:10

okuznetsov

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score 1 · Answer 3 · answered Jul 25 '16 at 14:10

1

You mean zip?

dict(zip(fees, names))

answered Jul 25 '16 at 14:10

RvdK

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score 1 · Answer 4 · answered Jul 25 '16 at 14:15

1

You want this

{fees[i]:y[i] for i in range(len(fees))}

or more quite :

dict(zip(fees, names))

answered Jul 25 '16 at 14:15

khelili miliana

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Make a list of dicts by iterating over two lists (list comprehensions)

4 Answers4