Problems with implode() function when I use global array

Question

I have the following code:

<?php
    $atributos = array("id","attr1","attr2","attr4");
    function dinamico()
    {
       $stringData = implode(",",$atributos);
       echo $stringData;
    } 
?>

and it give this:

Warning: implode(): Invalid arguments passed

if I declare this array inside function, It works but not out of it.

Note: I need to declare it outside because I use this array too times.

Your question title says global array, but you have not indicated it as global within your function. — Don't Panic, Jun 28 '16 at 22:09
nope you have to call a globals like $GLOBALS['atributos'] in the implode function.. see here for reference: http://www.w3schools.com/php/php_superglobals.asp — rahul, Jun 28 '16 at 22:09

Don't Panic · Answer 1 · 2016-06-28T22:22:35.553

To avoid using global, you can pass the array as an argument to your function.

<?php

function dinamico($atributos)  // add a parameter here
{
   $stringData = implode(",",$atributos);
   echo $stringData;
}

$atributos = array("id","attr1","attr2","attr4");  // declare the array outside the function

dinamico($atributos);  // pass the array to the function when you call it

An advantage to doing it this way rather than using global $atributos; inside your function (which would also work) is that it allows your function to be self-contained rather than forcing it to depend on the existence of a variable with a certain name outside its scope.

Problems with implode() function when I use global array

1 Answers1