Consider the following:
#define asd(a, b) a ## _ ## b
#define concat(a, b) a ## b
When I do:
concat(__, asd(x, y));
I would expect to get
__x_y
But no, the asd part is not evaluated as a macro. What am I supposed to do? I also tried directly with
__ ## asd(x, y)
But no, that doesn't work either. Is there any way to get what I need, i.e., the result of asd(x, y) to be used in concat instead of the explicit "asd(x, y)" expression?
