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How to make a Python class serializable?

class FileItem:
    def __init__(self, fname):
        self.fname = fname

Attempt to serialize to JSON:

>>> import json
>>> x = FileItem('/foo/bar')
>>> json.dumps(x)
TypeError: Object of type 'FileItem' is not JSON serializable
Mateen Ulhaq
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Sergey
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    It's unfortunate that the answers all seem to answer the question "How do I serialize a class?" rather than the action question "How do I make a class serializable?" These answers assume that you're doing the serialization yourself, rather than passing the object along to some other module that serializes it. – Kyle Delaney Oct 17 '19 at 23:59
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    If you're using Python3.5+, you could use jsons. It will convert your object (and ***all its attributes recursively***) to a dict. ```import jsons``` see answer below - it works perfectly fine – tswaehn Apr 02 '20 at 13:07
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    @KyleDelaney I was really hoping for an interface/magic method I could implement to become searializable too. I guess I will have to implement a `.to_dict()` function or something which can be called on the object before it is passed to the module which tries to serialize it. – Felix B. Sep 01 '20 at 19:09
  • see https://stackoverflow.com/a/63718624/1497139 for a start for a JSONAble mixin – Wolfgang Fahl Sep 03 '20 at 07:17
  • @FelixB. You can use the built-in `vars` function in combination with `json.dumps` (see my answer https://stackoverflow.com/a/64469761/1587520) – user1587520 Nov 23 '20 at 15:47
  • @FelixB. If it suits your use case, you could use a dataclass, which has it's own `.__dict__` – Joe Sadoski Sep 14 '21 at 13:25
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    It's amazing that in 11 years there has not been a single response that answers this question. OP states he wants to use `json.dumps` yet all the answers, including with the bounty awarded, involve creating a custom encoder, which dodges the point of the question entirely. – Mike Oct 15 '21 at 15:00
  • This article explains the specific methods of making a class serializable, which is exactly what the question asked: https://pynative.com/make-python-class-json-serializable/ – Asif Shiraz May 29 '22 at 21:20
  • @Mike a custom encoder is not required; a `default` hook - which is a simple parameter to `json.dumps` - suffices. One answer simply offers `json.dumps(..., default=vars)`. There's also an answer that does work solely by modifying the class: specifically, it must be modified to subtype `dict`. Your assessment of the answers is simply off base. – Karl Knechtel Jun 01 '22 at 15:59
  • That said, this question serves as a canonical now, so it's entirely reasonable that it attracts answers that tell beginners the right thing(s) to do. – Karl Knechtel Jun 01 '22 at 16:16

37 Answers37

782

Here is a simple solution for a simple feature:

.toJSON() Method

Instead of a JSON serializable class, implement a serializer method:

import json

class Object:
    def toJSON(self):
        return json.dumps(self, default=lambda o: o.__dict__, 
            sort_keys=True, indent=4)

So you just call it to serialize:

me = Object()
me.name = "Onur"
me.age = 35
me.dog = Object()
me.dog.name = "Apollo"

print(me.toJSON())

will output:

{
    "age": 35,
    "dog": {
        "name": "Apollo"
    },
    "name": "Onur"
}
Onur Yıldırım
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    Very limited. If you have a dict {"foo":"bar","baz":"bat"}, that will serialize to JSON easily. If instead you have {"foo":"bar","baz":MyObject()}, then you cannot. The ideal situation would be that nested objects are serialized to JSON recursively, not explicitly. – Mark E. Haase Aug 22 '13 at 18:51
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    It will still work. You're missing `o.__dict___`. Try your own example: `class MyObject(): def __init__(self): self.prop = 1 j = json.dumps({ "foo": "bar", "baz": MyObject() }, default=lambda o: o.__dict__)` – Onur Yıldırım Aug 22 '13 at 22:56
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    Is this solution reversible? I.e. Is it easy to reconstruct the object from json? – Jorge Leitao Apr 26 '15 at 18:20
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    @J.C.Leitão No. You could have two different classes with the same fields. Objects a and b of that class (probably with the same properties) would have the same `a.__dict__` / `b.__dict__`. – Martin Thoma Jun 16 '15 at 12:30
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    However, you could probably add a field `unjson_class` or so which gives a hint which class the object originally had. Then you could use introspection of your module and use something like http://stackoverflow.com/a/2169191/562769 to get the object back. – Martin Thoma Jun 16 '15 at 12:32
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    This does not work with `datetime.datetime` instances. It throws the following error: `'datetime.datetime' object has no attribute '__dict__'` – Bruno Finger Jun 17 '15 at 12:43
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    The following will work for anything that doesn't have a `__dict__`: `def _try(o): try: return o.__dict__ except: return str(o)` and `def to_JSON(self): return json.dumps(self, default=lambda o: _try(o), sort_keys=True, indent=0, separators=(',',':')).replace('\n', '')` – Bruno Finger Jun 17 '15 at 13:31
  • @J.C.Leitão yes, it is reversible. when you load the json you can add each key/value pair to the object __dict__ property see https://stackoverflow.com/questions/6578986/how-to-convert-json-data-into-a-python-object – FistOfFury Sep 03 '17 at 12:25
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    I must be missing something but that seems like it doesn't work (ie., `json.dumps(me)` doesn't call `Object`'s `toJSON` method. – cglacet Aug 24 '18 at 13:44
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    You can use `default=vars` instead of `default=lambda o: o.__dict__`. – Matthew D. Scholefield Feb 24 '19 at 03:49
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    @cglacet That is because he didn't make the class serializable, he just made a method that spits JSON String. This is not a proper answer for the question, it is more of a hack for special cases. But the correct one is above. If you would need YourObject getting serialized as a part/content of another ParentObject, you need to create an encoder. – Javo Sep 08 '20 at 14:44
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    The question specifically asks about making json.dumps(). Not how to implement all of JSON serialization yourself. – Ernest Oct 22 '20 at 23:16
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    744 people did not understand the question – Mike Oct 15 '21 at 15:10
  • I found this to be super useful for finding out what classes don't work (or just bypassing them). This assumes, of course, you don't care about missing some data. def default_serialize_func(o): if hasattr(o, '__dict__'): return o.__dict__ return f"" – cmyers Dec 07 '21 at 00:31
  • Wow, comments are supremely broken in formatting ability. Check out this gist for your eyes to stop bleeding: https://gist.github.com/terabyte/8b961c29eab7fd155ddbe115d7941326 – cmyers Dec 07 '21 at 00:39
  • I may be late but to serialize a `datetime` with classes in classes: `json.dumps(myObject, default=lambda o: o.isoformat() if (isinstance(o, datetime.datetime)) else o.__dict__, sort_keys=True, indent=4)` - Do not need to implement an additional function. – user12642493 May 10 '22 at 02:34
677

Do you have an idea about the expected output? For example, will this do?

>>> f  = FileItem("/foo/bar")
>>> magic(f)
'{"fname": "/foo/bar"}'

In that case you can merely call json.dumps(f.__dict__).

If you want more customized output then you will have to subclass JSONEncoder and implement your own custom serialization.

For a trivial example, see below.

>>> from json import JSONEncoder
>>> class MyEncoder(JSONEncoder):
        def default(self, o):
            return o.__dict__    

>>> MyEncoder().encode(f)
'{"fname": "/foo/bar"}'

Then you pass this class into the json.dumps() method as cls kwarg:

json.dumps(cls=MyEncoder)

If you also want to decode then you'll have to supply a custom object_hook to the JSONDecoder class. For example:

>>> def from_json(json_object):
        if 'fname' in json_object:
            return FileItem(json_object['fname'])
>>> f = JSONDecoder(object_hook = from_json).decode('{"fname": "/foo/bar"}')
>>> f
<__main__.FileItem object at 0x9337fac>
>>> 
mkrieger1
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Manoj Govindan
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    Using `__dict__` will not work in all cases. If the attributes have not been set after the object was instantiated, `__dict__` may not be fully populated. In the example above, you're OK, but if you have class attributes that you also want to encode, those will not be listed in `__dict__` unless they have been modified in the class' `__init__` call or by some other way after the object was instantiated. – Kris Hardy Dec 29 '11 at 16:41
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    +1, but the `from_json()` function used as object-hook should have an `else: return json_object` statement, so it can deal with general objects as well. – jogojapan Mar 19 '13 at 07:51
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    @KrisHardy `__dict__` also doesn't work if you use `__slots__` on a new style class. – badp Dec 13 '13 at 17:53
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    You could use a custom `JSONEncoder` as above to create a custom protocol, such as checking for the existence of `__json_serializable__` method and calling it to obtain a JSON serializable representation of the object. This would be in keeping with other Python patterns, like `__getitem__`, `__str__`, `__eq__`, and `__len__`. – jpmc26 Jul 15 '15 at 00:53
  • am new to python...can we use these libraries (`json` or `simplejson`) to serialize/deserialize objects which are extensively used by python developers say pandas dataframe, series etc? – Mahesha999 Sep 20 '16 at 07:29
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    `__dict__` also won't work recursively, e.g., if an attribute of your object is another object. – Neel Apr 10 '18 at 19:12
  • `JSONEncoder` only call subclass's `default` method if the given data if non-standard. – yoonghm Sep 18 '18 at 05:55
  • @Mahesha999 use the df.to_json() method for Dataframe, Series, etc – user2561747 Dec 07 '18 at 00:25
223

For more complex classes you could consider the tool jsonpickle:

jsonpickle is a Python library for serialization and deserialization of complex Python objects to and from JSON.

The standard Python libraries for encoding Python into JSON, such as the stdlib’s json, simplejson, and demjson, can only handle Python primitives that have a direct JSON equivalent (e.g. dicts, lists, strings, ints, etc.). jsonpickle builds on top of these libraries and allows more complex data structures to be serialized to JSON. jsonpickle is highly configurable and extendable–allowing the user to choose the JSON backend and add additional backends.

(link to jsonpickle on PyPi)

mrnom
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gecco
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    Coming from C#, this is what I was expecting. A simple one liner and no messing with the classes. – Jerther Dec 13 '15 at 22:34
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    jsonpickle is awesome. It worked perfectly for a huge, complex, messy object with many levels of classes – wisbucky Mar 04 '16 at 18:23
  • is there an example of the proper way to save this to a file? The documentation only shows how to encode and decode a `jsonpickle` object. Also, this was not able to decode a dict of dicts containing pandas dataframes. – user5359531 Aug 16 '16 at 17:14
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    @user5359531 you can use `obj = jsonpickle.decode(file.read())` and `file.write(jsonpickle.encode(obj))`. – Kilian Batzner Jan 02 '17 at 08:04
  • It works for me!. It is what I needed. I just wanted to print a behave scenario object. – matabares May 26 '20 at 15:06
  • This is a great solution. Rather than building a complex JSON decoder extension for the json module, I was able to serialize my class with one line: s=jsonpickle.encode(self). Restoration was every bit as simple. This is the true Python spirit. +1 – NoCake Sep 18 '20 at 13:52
  • Sadly, doesn't seem to work on a openpyxl spreadsheet. I'm trying to turn a spreadsheet into .json, write it to a file, which works great. Then read that .json file back in, decode and save back to Excel. Unfortunately it fails on decode with `Cannot convert [] to Excel`. – johnjps111 Feb 01 '22 at 05:21
  • Just have to be careful that you don't expose yourself to RCE if deserializing data from untrusted sources – xlm Mar 14 '22 at 05:00
  • As a side note, if using redis to stream, replace `json.dumps()` and `json.loads()` with `jsonpickle.encode()` and `jsonpickle.decode()`. You will save having to write tons of boiler-plate code! – kfmfe04 Apr 07 '22 at 21:56
164

Most of the answers involve changing the call to json.dumps(), which is not always possible or desirable (it may happen inside a framework component for example).

If you want to be able to call json.dumps(obj) as is, then a simple solution is inheriting from dict:

class FileItem(dict):
    def __init__(self, fname):
        dict.__init__(self, fname=fname)

f = FileItem('tasks.txt')
json.dumps(f)  #No need to change anything here

This works if your class is just basic data representation, for trickier things you can always set keys explicitly.

andyhasit
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    This can really be a nice solution :) I believe for my case it is. Benefits: you communicate the "shape" of the object by making it a class with init, it is inherently serializable and it looks interpretable as __repr__. – PascalVKooten Sep 22 '16 at 19:41
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    Though "dot-access" is still missing :( – PascalVKooten Sep 22 '16 at 19:46
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    Ahh that seems to work! Thanks, not sure why this is not the accepted answer. I totally agree that changing the `dumps` is not a good solution. By the way, in most cases you probably want to have `dict` inheritance together with delegation, which means that you will have some `dict` type attribute inside your class, you will then pass this attribute as parameter as initialisation something like `super().__init__(self.elements)`. – cglacet Aug 24 '18 at 13:52
  • In my use case I needed to store data that was "invisible" to json.dumps(), so I used this method. The class DictWithRider takes in an arbitrary object, stores it as a member, and makes it accessible via a function get_rider_obj() but does not pass it to dict.__init__(). So parts of the application who want to see the "hidden" data can call d.get_rider_obj() but json.dumps() sees basically an empty dict. As @PascalVKooten mentioned, you can't access regular members with dot notation, but you can access functions. – gkimsey Jul 21 '20 at 15:48
  • for simple use this is ideal. dot notation can be easily enabled by additional lines subsequent to ```dict.__init__(``` line as ```self.fname = fname``` and the object can be deserialised with ```f = FileItem(**json.loads(serialised_f))``` – paddyg Jan 21 '21 at 09:34
  • I absolutely love this one for its simplicity. You have to design your classes completely (no monkey-patching), but it works really nicely, even if your class members are lists of objects. – Cerno May 03 '21 at 15:34
  • 6 years later, this is still the best answer – rossco Jul 09 '21 at 05:27
  • This is exactly what I need, thank you so much – Qingyi Wu Jul 19 '21 at 16:05
  • I think this is closest to a correct answer to the question. It helped me a lot thanks :) – Philip Z. Nov 11 '21 at 11:04
  • for "dot-access" I recommend using properties instead of adding additional attributes – sluki Jan 24 '22 at 13:02
  • this should definitely be added to the most recommended answer – sale108 Mar 19 '22 at 21:40
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    this solution's a bit hacky - for a true, production quality solution, replace json.dumps() and json.loads() with jsonpickle.encode() and jsonpickle.decode(). You will avoid having to write ugly boilerplate code, and most importantly, if you are able to pickle the object, you should be able to serialize it with jsonpickle without boilerplate code (complex containers/objects will just work). – kfmfe04 Apr 07 '22 at 22:07
  • @kfmfe04 this answer addresses cases where you have no control over the code which calls `json.dumps`. – andyhasit Apr 08 '22 at 09:47
89

As mentioned in many other answers you can pass a function to json.dumps to convert objects that are not one of the types supported by default to a supported type. Surprisingly none of them mentions the simplest case, which is to use the built-in function vars to convert objects into a dict containing all their attributes:

json.dumps(obj, default=vars)

Note that this covers only basic cases, if you need more specific serialization for certain types (e.g. exluding certain attributes or for objects that don't have a __dict__ attribute) you need to use a custom function or a JSONEncoder as desribed in the other answers.

user1587520
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    it is unclear what you mean by `default=vars`, does that mean that `vars` is the default serializer? If not: This does not really solve the case where you can not influence how `json.dumps` is called. If you simply pass an object to a library and that library calls `json.dumps` on that object, it doesn't really help that you have implemented `vars` if that library does not use `dumps` this way. In that sense it is equivalent to a custom `JSONEncoder`. – Felix B. Nov 24 '20 at 14:39
  • You are correct, it is nothing else than just a simple choice for a custom serializer and doesn't solve the case you describe. If I see it correctly there is no solution to the case were you don't control how `json.dumps` is invoked. – user1587520 Nov 25 '20 at 08:01
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    For some objects, this approach will throw `vars() argument must have __dict__ attribute` – JustAMartin Feb 24 '21 at 14:04
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    this is probably the best solution, least intrusive, and easiest to understand – Leonmax Sep 22 '21 at 07:07
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    Thanks for this, pretty straightforward to use with library that have proper definition built in. – PK214 Oct 22 '21 at 07:41
  • TY :: beautifully simple – gdibble Dec 19 '21 at 08:53
67

Just add to_json method to your class like this:

def to_json(self):
  return self.message # or how you want it to be serialized

And add this code (from this answer), to somewhere at the top of everything:

from json import JSONEncoder

def _default(self, obj):
    return getattr(obj.__class__, "to_json", _default.default)(obj)

_default.default = JSONEncoder().default
JSONEncoder.default = _default

This will monkey-patch json module when it's imported, so JSONEncoder.default() automatically checks for a special to_json() method and uses it to encode the object if found.

Just like Onur said, but this time you don't have to update every json.dumps() in your project.

Cadoiz
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Fancy John
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    Big thanks! This is the only answer that allows me to do what I want: be able to serialize an object without changing the existing code. The other methods mostly do not work for me. The object is defined in a third-party library, and the serialization code is third-party too. Changing them will be awkward. With your method, I only need to do `TheObject.to_json = my_serializer`. – Yongwei Wu Oct 11 '17 at 13:12
  • This is the correct answer. I did a small variation: ```import json _fallback = json._default_encoder.default json._default_encoder.default = lambda obj: getattr(obj.__class__, "to_json", _fallback)(obj) ``` – Kjir Nov 23 '21 at 21:39
64

I like Onur's answer but would expand to include an optional toJSON() method for objects to serialize themselves:

def dumper(obj):
    try:
        return obj.toJSON()
    except:
        return obj.__dict__
print json.dumps(some_big_object, default=dumper, indent=2)
Community
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Jason S
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  • I found this to be the best balance between using the existing `json.dumps` and introducing custom handling. Thanks! – Daniel Buckmaster Apr 15 '15 at 00:52
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    I actually really like this; but rather than `try-catch` would probably do something like `if 'toJSON' in obj.__attrs__():`... to avoid a silent failure (in the event of failure in toJSON() for some other reason than it not being there)... a failure which potentially leads to data corruption. – thclark Nov 22 '17 at 18:29
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    @thclark as I understand it, idomatic python asks for forgiveness, not permission, so try-except is the right approach, but the correct exception should be caught, an AttributeError in this case. – Phil Sep 08 '20 at 04:43
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    @phil a few years older and wiser now, I'd agree with you. – thclark Sep 08 '20 at 09:49
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    This really should be catching an `AttributeError` explicitly – juanpa.arrivillaga Feb 04 '21 at 16:08
  • And what if `AttributeError` is raised inside `obj.toJSON()`? – artm May 16 '21 at 09:17
42

Another option is to wrap JSON dumping in its own class:

import json

class FileItem:
    def __init__(self, fname):
        self.fname = fname

    def __repr__(self):
        return json.dumps(self.__dict__)

Or, even better, subclassing FileItem class from a JsonSerializable class:

import json

class JsonSerializable(object):
    def toJson(self):
        return json.dumps(self.__dict__)

    def __repr__(self):
        return self.toJson()


class FileItem(JsonSerializable):
    def __init__(self, fname):
        self.fname = fname

Testing:

>>> f = FileItem('/foo/bar')
>>> f.toJson()
'{"fname": "/foo/bar"}'
>>> f
'{"fname": "/foo/bar"}'
>>> str(f) # string coercion
'{"fname": "/foo/bar"}'
user222758
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    Hi, I don't really like this "custom encoder" approach, it would be better if u can make your class json seriazable. I try, and try and try and nothing. Is there any idea how to do this. The thing is that json module test your class against built in python types, and even says for custom classes make your encoder :). Can it be faked? So I could do something to my class so it behave like simple list to json module? I try __subclasscheck__ and __instancecheck__ but nothing. – Bojan Radojevic Aug 15 '12 at 12:43
  • @ADRENALIN You could inherit from a primary type (probably dict), if all class attribute values are serializable and you don't mind hacks. You could also use jsonpickle or json_tricks or something instead of the standard one (still a custom encoder, but not one you need to write or call). The former pickles the instance, the latter stores it as dict of attributes, which you can change by implementing `__json__encode__` / `__json_decode__` (disclosure: I made the last one). – Mark Oct 20 '16 at 13:02
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    That doesn't make the object serializeable for the json class. It only provides a method to get a json string returned (trivial). Thus `json.dumps(f)` will fail. That's not what's been asked. – omni Sep 21 '20 at 14:38
36

If you're using Python3.5+, you could use jsons. (PyPi: https://pypi.org/project/jsons/) It will convert your object (and all its attributes recursively) to a dict.

import jsons

a_dict = jsons.dump(your_object)

Or if you wanted a string:

a_str = jsons.dumps(your_object)

Or if your class implemented jsons.JsonSerializable:

a_dict = your_object.json
R H
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    If you are able to use Python 3.7+, I found that the cleanest solution to convert python classes to dicts and JSON strings (and viceversa) is to mix the `jsons` library with [dataclasses](https://docs.python.org/3.7/library/dataclasses.html). So far, so good for me! – Ruluk Feb 26 '19 at 16:02
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    This is an external library, not built into the standard Python install. – Noumenon Jul 10 '19 at 02:44
  • only for class that has __slots__ attribute – yehudahs Dec 03 '19 at 20:41
  • You can, but you don't need to use __slots__. Only when dumping according to the signature of a specific class you'll need __slots__. In the upcoming version 1.1.0 that is also no longer the case. – R H Dec 04 '19 at 13:30
  • This library is extremely slow in both deserialization/serialization, at least from personal testing. I'd suggest other ser libraries instead. – rv.kvetch Nov 30 '21 at 19:14
  • thank you. this worked perfectly – zaheer Dec 28 '21 at 11:06
  • How are you charting the JSON in the visuals/images? By the way this works. `json.dumps(obj)` then `json.loads(obj)`. – RustyShackleford Dec 30 '21 at 02:26
  • One still-missing feature is an option for human consumption / readability. Pretty-printing / indenting is not yet implemented (at least not yet as of v1.6.1). – Sam Feb 15 '22 at 16:37
33

I came across this problem the other day and implemented a more general version of an Encoder for Python objects that can handle nested objects and inherited fields:

import json
import inspect

class ObjectEncoder(json.JSONEncoder):
    def default(self, obj):
        if hasattr(obj, "to_json"):
            return self.default(obj.to_json())
        elif hasattr(obj, "__dict__"):
            d = dict(
                (key, value)
                for key, value in inspect.getmembers(obj)
                if not key.startswith("__")
                and not inspect.isabstract(value)
                and not inspect.isbuiltin(value)
                and not inspect.isfunction(value)
                and not inspect.isgenerator(value)
                and not inspect.isgeneratorfunction(value)
                and not inspect.ismethod(value)
                and not inspect.ismethoddescriptor(value)
                and not inspect.isroutine(value)
            )
            return self.default(d)
        return obj

Example:

class C(object):
    c = "NO"
    def to_json(self):
        return {"c": "YES"}

class B(object):
    b = "B"
    i = "I"
    def __init__(self, y):
        self.y = y
        
    def f(self):
        print "f"

class A(B):
    a = "A"
    def __init__(self):
        self.b = [{"ab": B("y")}]
        self.c = C()

print json.dumps(A(), cls=ObjectEncoder, indent=2, sort_keys=True)

Result:

{
  "a": "A", 
  "b": [
    {
      "ab": {
        "b": "B", 
        "i": "I", 
        "y": "y"
      }
    }
  ], 
  "c": {
    "c": "YES"
  }, 
  "i": "I"
}
np_6
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tobigue
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    Although this is a bit old..I'm facing some circular imports error. So instead of `return obj` in the last line I did this `return super(ObjectEncoder, self).default(obj)`. Reference [HERE](http://stackoverflow.com/questions/14249115/serializing-output-to-json-valueerror-circular-reference-detected) – SomeTypeFoo Apr 11 '17 at 13:44
21

The Real Answer to "making a *Class* serializable"

_

TLDR: while you can copy-paste Option 2 (below) Option 1 is better

Explanation:

  • While there is a viable solution, there is no python "official" solution.
    • By official solution, I mean there is no way (as of 2022) to add a method to your class (like toJSON in JavaScript) and no way to register your class with the built-in json module. When something like json.dumps([1,2, your_obj]) is executed, python doesn't check a lookup table or object method.
    • I'm not sure why other answers don't explain this
    • The closest official approach is probably andyhasit's answer which is to inherit from a dictionary. However, inheriting from a dictionary doesn't work very well for many custom classes like AdvancedDateTime, or pytorch tensors.
  • The ideal workaround is this:
    • Mutate json.dumps (affects everywhere, even pip modules that import json)
    • Add def __json__(self) method to your class

_

Option 1: Let a Module do the Patching

(extended + packaged version of Fancy John's answer, thank you @FancyJohn)
pip install json-fix

Step 1:

your_class_definition.py

import json_fix

class YOUR_CLASS:
    def __json__(self):
        # YOUR CUSTOM CODE HERE
        #    you probably just want to do:
        #        return self.__dict__
        return "a built-in object that is naturally json-able"

Step 2:

  • There is no step 2. It just works.
    (see option 2 if you want an explanation)

Example usage:

from your_class_definition import YOUR_CLASS
import json

json.dumps([1,2, YOUR_CLASS()], indent=0)
# '[\n1,\n2,\n"a built-in object that is naturally json-able"\n]'

_

For Pandas DataFrames, Numpy arrays, and other 3rd party objects you want to be json-able, see the Module on how to make them json-able with ~2 lines of code.

_

Option 2: Patch json.dumps yourself

Note: this approach is simplified, and misses out on controlling the json behavior for external classes (numpy arrays, datetime, dataframes, tensors, etc).

some_file_thats_imported_before_your_class_definitions.py

# Step: 1
# create the patch
from json import JSONEncoder
def wrapped_default(self, obj):
    return getattr(obj.__class__, "__json__", wrapped_default.default)(obj)
wrapped_default.default = JSONEncoder().default
   
# apply the patch
JSONEncoder.original_default = JSONEncoder.default
JSONEncoder.default = wrapped_default

your_class_definition.py

# Step 2
class YOUR_CLASS:
    def __json__(self, **options):
        # YOUR CUSTOM CODE HERE
        #    you probably just want to do:
        #        return self.__dict__
        return "a built-in object that is natually json-able"

_

All other answers seem to be "Best practices/approaches to serializing a custom object"

  • Which, is alreadly covered here in the docs (search "complex" for an example of encoding complex numbers)
Jeff Hykin
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14
import simplejson

class User(object):
    def __init__(self, name, mail):
        self.name = name
        self.mail = mail

    def _asdict(self):
        return self.__dict__

print(simplejson.dumps(User('alice', 'alice@mail.com')))

if using standard json, you need to define a default function

import json
def default(o):
    return o._asdict()

print(json.dumps(User('alice', 'alice@mail.com'), default=default))
jtlz2
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tryer3000
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    I simplifed this by removing the _asdict function with a lambda ```json.dumps(User('alice', 'alice@mail.com'), default=lambda x: x.__dict__)``` – JustEngland Nov 29 '18 at 16:56
8

json is limited in terms of objects it can print, and jsonpickle (you may need a pip install jsonpickle) is limited in terms it can't indent text. If you would like to inspect the contents of an object whose class you can't change, I still couldn't find a straighter way than:

 import json
 import jsonpickle
 ...
 print  json.dumps(json.loads(jsonpickle.encode(object)), indent=2)

Note: that still they can't print the object methods.

Martlark
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ribamar
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5

Here is my 3 cents ...
This demonstrates explicit json serialization for a tree-like python object.
Note: If you actually wanted some code like this you could use the twisted FilePath class.

import json, sys, os

class File:
    def __init__(self, path):
        self.path = path

    def isdir(self):
        return os.path.isdir(self.path)

    def isfile(self):
        return os.path.isfile(self.path)

    def children(self):        
        return [File(os.path.join(self.path, f)) 
                for f in os.listdir(self.path)]

    def getsize(self):        
        return os.path.getsize(self.path)

    def getModificationTime(self):
        return os.path.getmtime(self.path)

def _default(o):
    d = {}
    d['path'] = o.path
    d['isFile'] = o.isfile()
    d['isDir'] = o.isdir()
    d['mtime'] = int(o.getModificationTime())
    d['size'] = o.getsize() if o.isfile() else 0
    if o.isdir(): d['children'] = o.children()
    return d

folder = os.path.abspath('.')
json.dump(File(folder), sys.stdout, default=_default)
Dan Brough
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5

This class can do the trick, it converts object to standard json .

import json


class Serializer(object):
    @staticmethod
    def serialize(object):
        return json.dumps(object, default=lambda o: o.__dict__.values()[0])

usage:

Serializer.serialize(my_object)

working in python2.7 and python3.

Lost Koder
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  • I liked this method the most. I ran into issues when trying to serialize more complex objects whos members/methods aren't serializable. Here's my implementation that works on more objects: ``` class Serializer(object): @staticmethod def serialize(obj): def check(o): for k, v in o.__dict__.items(): try: _ = json.dumps(v) o.__dict__[k] = v except TypeError: o.__dict__[k] = str(v) return o return json.dumps(check(obj).__dict__, indent=2) ``` – Will Charlton Nov 11 '17 at 05:34
4
import json

class Foo(object):
    def __init__(self):
        self.bar = 'baz'
        self._qux = 'flub'

    def somemethod(self):
        pass

def default(instance):
    return {k: v
            for k, v in vars(instance).items()
            if not str(k).startswith('_')}

json_foo = json.dumps(Foo(), default=default)
assert '{"bar": "baz"}' == json_foo

print(json_foo)
rectangletangle
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  • From [doc](http://docs.python.org/3.4/library/json.html#json.dumps): The parameter ``default(obj)`` is a function that should return a serializable version of obj or raise TypeError. The default ``default`` simply raises TypeError. – luckydonald Jun 28 '16 at 16:09
4

jaraco gave a pretty neat answer. I needed to fix some minor things, but this works:

Code

# Your custom class
class MyCustom(object):
    def __json__(self):
        return {
            'a': self.a,
            'b': self.b,
            '__python__': 'mymodule.submodule:MyCustom.from_json',
        }

    to_json = __json__  # supported by simplejson

    @classmethod
    def from_json(cls, json):
        obj = cls()
        obj.a = json['a']
        obj.b = json['b']
        return obj

# Dumping and loading
import simplejson

obj = MyCustom()
obj.a = 3
obj.b = 4

json = simplejson.dumps(obj, for_json=True)

# Two-step loading
obj2_dict = simplejson.loads(json)
obj2 = MyCustom.from_json(obj2_dict)

# Make sure we have the correct thing
assert isinstance(obj2, MyCustom)
assert obj2.__dict__ == obj.__dict__

Note that we need two steps for loading. For now, the __python__ property is not used.

How common is this?

Using the method of AlJohri, I check popularity of approaches:

Serialization (Python -> JSON):

Deserialization (JSON -> Python):

Martin Thoma
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4

This has worked well for me:

class JsonSerializable(object):

    def serialize(self):
        return json.dumps(self.__dict__)

    def __repr__(self):
        return self.serialize()

    @staticmethod
    def dumper(obj):
        if "serialize" in dir(obj):
            return obj.serialize()

        return obj.__dict__

and then

class FileItem(JsonSerializable):
    ...

and

log.debug(json.dumps(<my object>, default=JsonSerializable.dumper, indent=2))
jmhostalet
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3

If you don't mind installing a package for it, you can use json-tricks:

pip install json-tricks

After that you just need to import dump(s) from json_tricks instead of json, and it'll usually work:

from json_tricks import dumps
json_str = dumps(cls_instance, indent=4)

which'll give

{
        "__instance_type__": [
                "module_name.test_class",
                "MyTestCls"
        ],
        "attributes": {
                "attr": "val",
                "dct_attr": {
                        "hello": 42
                }
        }
}

And that's basically it!


This will work great in general. There are some exceptions, e.g. if special things happen in __new__, or more metaclass magic is going on.

Obviously loading also works (otherwise what's the point):

from json_tricks import loads
json_str = loads(json_str)

This does assume that module_name.test_class.MyTestCls can be imported and hasn't changed in non-compatible ways. You'll get back an instance, not some dictionary or something, and it should be an identical copy to the one you dumped.

If you want to customize how something gets (de)serialized, you can add special methods to your class, like so:

class CustomEncodeCls:
        def __init__(self):
                self.relevant = 42
                self.irrelevant = 37

        def __json_encode__(self):
                # should return primitive, serializable types like dict, list, int, string, float...
                return {'relevant': self.relevant}

        def __json_decode__(self, **attrs):
                # should initialize all properties; note that __init__ is not called implicitly
                self.relevant = attrs['relevant']
                self.irrelevant = 12

which serializes only part of the attributes parameters, as an example.

And as a free bonus, you get (de)serialization of numpy arrays, date & times, ordered maps, as well as the ability to include comments in json.

Disclaimer: I created json_tricks, because I had the same problem as you.

Mark
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3

Kyle Delaney's comment is correct so i tried to use the answer https://stackoverflow.com/a/15538391/1497139 as well as an improved version of https://stackoverflow.com/a/10254820/1497139

to create a "JSONAble" mixin.

So to make a class JSON serializeable use "JSONAble" as a super class and either call:

 instance.toJSON()

or

 instance.asJSON()

for the two offered methods. You could also extend the JSONAble class with other approaches offered here.

The test example for the Unit Test with Family and Person sample results in:

toJSOn():

{
    "members": {
        "Flintstone,Fred": {
            "firstName": "Fred",
            "lastName": "Flintstone"
        },
        "Flintstone,Wilma": {
            "firstName": "Wilma",
            "lastName": "Flintstone"
        }
    },
    "name": "The Flintstones"
}

asJSOn():

{'name': 'The Flintstones', 'members': {'Flintstone,Fred': {'firstName': 'Fred', 'lastName': 'Flintstone'}, 'Flintstone,Wilma': {'firstName': 'Wilma', 'lastName': 'Flintstone'}}}

Unit Test with Family and Person sample

def testJsonAble(self):
        family=Family("The Flintstones")
        family.add(Person("Fred","Flintstone")) 
        family.add(Person("Wilma","Flintstone"))
        json1=family.toJSON()
        json2=family.asJSON()
        print(json1)
        print(json2)

class Family(JSONAble):
    def __init__(self,name):
        self.name=name
        self.members={}
    
    def add(self,person):
        self.members[person.lastName+","+person.firstName]=person

class Person(JSONAble):
    def __init__(self,firstName,lastName):
        self.firstName=firstName;
        self.lastName=lastName;

jsonable.py defining JSONAble mixin

 '''
Created on 2020-09-03

@author: wf
'''
import json

class JSONAble(object):
    '''
    mixin to allow classes to be JSON serializable see
    https://stackoverflow.com/questions/3768895/how-to-make-a-class-json-serializable
    '''

    def __init__(self):
        '''
        Constructor
        '''
    
    def toJSON(self):
        return json.dumps(self, default=lambda o: o.__dict__, 
            sort_keys=True, indent=4)
        
    def getValue(self,v):
        if (hasattr(v, "asJSON")):
            return v.asJSON()
        elif type(v) is dict:
            return self.reprDict(v)
        elif type(v) is list:
            vlist=[]
            for vitem in v:
                vlist.append(self.getValue(vitem))
            return vlist
        else:   
            return v
    
    def reprDict(self,srcDict):
        '''
        get my dict elements
        '''
        d = dict()
        for a, v in srcDict.items():
            d[a]=self.getValue(v)
        return d
    
    def asJSON(self):
        '''
        recursively return my dict elements
        '''
        return self.reprDict(self.__dict__)   

You'll find these approaches now integrated in the https://github.com/WolfgangFahl/pyLoDStorage project which is available at https://pypi.org/project/pylodstorage/

Wolfgang Fahl
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2

jsonweb seems to be the best solution for me. See http://www.jsonweb.info/en/latest/

from jsonweb.encode import to_object, dumper

@to_object()
class DataModel(object):
  def __init__(self, id, value):
   self.id = id
   self.value = value

>>> data = DataModel(5, "foo")
>>> dumper(data)
'{"__type__": "DataModel", "id": 5, "value": "foo"}'
matthewlent
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2

Building on Quinten Cabo's answer:

def sterilize(obj):
    """Make an object more ameniable to dumping as json
    """
    if type(obj) in (str, float, int, bool, type(None)):
        return obj
    elif isinstance(obj, dict):
        return {k: sterilize(v) for k, v in obj.items()}
    list_ret = []
    dict_ret = {}
    for a in dir(obj):
        if a == '__iter__' and callable(obj.__iter__):
            list_ret.extend([sterilize(v) for v in obj])
        elif a == '__dict__':
            dict_ret.update({k: sterilize(v) for k, v in obj.__dict__.items() if k not in ['__module__', '__dict__', '__weakref__', '__doc__']})
        elif a not in ['__doc__', '__module__']:
            aval = getattr(obj, a)
            if type(aval) in (str, float, int, bool, type(None)):
                dict_ret[a] = aval
            elif a != '__class__' and a != '__objclass__' and isinstance(aval, type):
                dict_ret[a] = sterilize(aval)
    if len(list_ret) == 0:
        if len(dict_ret) == 0:
            return repr(obj)
        return dict_ret
    else:
        if len(dict_ret) == 0:
            return list_ret
    return (list_ret, dict_ret)

The differences are

  1. Works for any iterable instead of just list and tuple (it works for NumPy arrays, etc.)
  2. Works for dynamic types (ones that contain a __dict__).
  3. Includes native types float and None so they don't get converted to string.
  4. Classes that have __dict__ and members will mostly work (if the __dict__ and member names collide, you will only get one - likely the member)
  5. Classes that are lists and have members will look like a tuple of the list and a dictionary
  6. Python3 (that isinstance() call may be the only thing that needs changing)
mheyman
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2
class DObject(json.JSONEncoder):
    def delete_not_related_keys(self, _dict):
        for key in ["skipkeys", "ensure_ascii", "check_circular", "allow_nan", "sort_keys", "indent"]:
            try:
                del _dict[key]
            except:
                continue

    def default(self, o):
        if hasattr(o, '__dict__'):
            my_dict = o.__dict__.copy()
            self.delete_not_related_keys(my_dict)
            return my_dict
        else:
            return o

a = DObject()
a.name = 'abdul wahid'
b = DObject()
b.name = a

print(json.dumps(b, cls=DObject))
Sheikh Abdul Wahid
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1

I liked Lost Koder's method the most. I ran into issues when trying to serialize more complex objects whos members/methods aren't serializable. Here's my implementation that works on more objects:

class Serializer(object):
    @staticmethod
    def serialize(obj):
        def check(o):
            for k, v in o.__dict__.items():
                try:
                    _ = json.dumps(v)
                    o.__dict__[k] = v
                except TypeError:
                    o.__dict__[k] = str(v)
            return o
        return json.dumps(check(obj).__dict__, indent=2)
Will Charlton
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1

I ran into this problem when I tried to store Peewee's model into PostgreSQL JSONField.

After struggling for a while, here's the general solution.

The key to my solution is going through Python's source code and realizing that the code documentation (described here) already explains how to extend the existing json.dumps to support other data types.

Suppose you current have a model that contains some fields that are not serializable to JSON and the model that contains the JSON field originally looks like this:

class SomeClass(Model):
    json_field = JSONField()

Just define a custom JSONEncoder like this:

class CustomJsonEncoder(json.JSONEncoder):
    def default(self, obj):
        if isinstance(obj, SomeTypeUnsupportedByJsonDumps):
            return < whatever value you want >
        return json.JSONEncoder.default(self, obj)

    @staticmethod
    def json_dumper(obj):
        return json.dumps(obj, cls=CustomJsonEncoder)

And then just use it in your JSONField like below:

class SomeClass(Model):
    json_field = JSONField(dumps=CustomJsonEncoder.json_dumper)

The key is the default(self, obj) method above. For every single ... is not JSON serializable complaint you receive from Python, just add code to handle the unserializable-to-JSON type (such as Enum or datetime)

For example, here's how I support a class inheriting from Enum:

class TransactionType(Enum):
   CURRENT = 1
   STACKED = 2

   def default(self, obj):
       if isinstance(obj, TransactionType):
           return obj.value
       return json.JSONEncoder.default(self, obj)

Finally, with the code implemented like above, you can just convert any Peewee models to be a JSON-seriazable object like below:

peewee_model = WhateverPeeweeModel()
new_model = SomeClass()
new_model.json_field = model_to_dict(peewee_model)

Though the code above was (somewhat) specific to Peewee, but I think:

  1. It's applicable to other ORMs (Django, etc) in general
  2. Also, if you understood how json.dumps works, this solution also works with Python (sans ORM) in general too

Any questions, please post in the comments section. Thanks!

sivabudh
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1

First we need to make our object JSON-compliant, so we can dump it using the standard JSON module. I did it this way:

def serialize(o):
    if isinstance(o, dict):
        return {k:serialize(v) for k,v in o.items()}
    if isinstance(o, list):
        return [serialize(e) for e in o]
    if isinstance(o, bytes):
        return o.decode("utf-8")
    return o
Adi Degani
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1

This function uses recursion to iterate over every part of the dictionary and then calls the repr() methods of classes that are not build-in types.

def sterilize(obj):
    object_type = type(obj)
    if isinstance(obj, dict):
        return {k: sterilize(v) for k, v in obj.items()}
    elif object_type in (list, tuple):
        return [sterilize(v) for v in obj]
    elif object_type in (str, int, bool, float):
        return obj
    else:
        return obj.__repr__()
Quinten Cabo
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1

To throw another log on this 11 year old fire, I want a solution that meets the following criteria:

  • Allows an instance of class FileItem to be serialized using only json.dumps(obj)
  • Allows FileItem instances to have properties: fileItem.fname
  • Allows FileItem instances to be given to any library which will serialise it using json.dumps(obj)
  • Doesn't require any other fields to be passed to json.dumps (like a custom serializer)

IE:

fileItem = FileItem('filename.ext')
assert json.dumps(fileItem) == '{"fname": "filename.ext"}'
assert fileItem.fname == 'filename.ext'

My solution is:

  • Have obj's class inherit from dict
  • Map each object property to the underlying dict
class FileItem(dict):
    def __init__(self, fname):
        self['fname'] = fname

    #fname property
    fname: str = property()
    @fname.getter
    def fname(self):
        return self['fname']

    @fname.setter
    def fname(self, value: str):
        self['fname'] = value

    #Repeat for other properties

Yes, this is somewhat long winded if you have lots of properties, but it is JSONSerializable and it behaves like an object and you can give it to any library that's going to json.dumps(obj) it.

Daniel Flippance
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1

Why are you guys making it so complicated? Here is a simple example:

#!/usr/bin/env python3

import json
from dataclasses import dataclass

@dataclass
class Person:
    first: str
    last: str
    age: int

    @property
    def __json__(self):
        return {
            "name": f"{self.first} {self.last}",
            "age": self.age
        }

john = Person("John", "Doe", 42)
print(json.dumps(john, indent=4, default=lambda x: x.__json__))

This way you could also serialize nested classes, as __json__ returns a python object and not a string. No need to use a JSONEncoder, as the default parameter with a simple lambda also works fine.

I've used @property instead of a simple function, as this feels more natural and modern. The @dataclass is also just an example, it works for a "normal" class as well.

NicoHood
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  • possibly because you'd need to define a `__json__` property for each class, which can be sometimes a pain. also, dataclasses provides `asdict` so technically you don't need a `__json__` property at all. – rv.kvetch May 15 '22 at 16:34
  • Sure, but what if you want to represent the json in a different way? Like in this case I combine first and last name. Thje `asdict` would not work for nested elements, right? – NicoHood May 16 '22 at 10:55
  • hmm, in that case I would suggest making first and last as `InitVar` (init-only) fields, and setting name field in the `__post_init__` constructor. I think that should hopefully work to represent json in a diff format in this case. Also, i might be wrong but I believe `asdict` works for nested dataclasses as well. – rv.kvetch May 16 '22 at 13:04
  • But that does not work if you change the variables later on. – NicoHood May 16 '22 at 16:39
  • Hmm, to best of my understanding it should. can you provide an example of what you mean? – rv.kvetch May 16 '22 at 17:13
  • [First Comment on main question] "These answers assume that you're doing the serialization yourself, rather than passing the object along to some other module that serializes it. – Kyle Delaney Oct 17, 2019" I think that sums up the issue – Jeff Hykin May 16 '22 at 19:43
0

This is a small library that serializes an object with all its children to JSON and also parses it back:

https://github.com/tobiasholler/PyJSONSerialization/

Community
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Tobi
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0

I came up with my own solution. Use this method, pass any document (dict,list, ObjectId etc) to serialize.

def getSerializable(doc):
    # check if it's a list
    if isinstance(doc, list):
        for i, val in enumerate(doc):
            doc[i] = getSerializable(doc[i])
        return doc

    # check if it's a dict
    if isinstance(doc, dict):
        for key in doc.keys():
            doc[key] = getSerializable(doc[key])
        return doc

    # Process ObjectId
    if isinstance(doc, ObjectId):
        doc = str(doc)
        return doc

    # Use any other custom serializting stuff here...

    # For the rest of stuff
    return doc
Dewsworld
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0

If you are able to install a package, I'd recommend trying dill, which worked just fine for my project. A nice thing about this package is that it has the same interface as pickle, so if you have already been using pickle in your project you can simply substitute in dill and see if the script runs, without changing any code. So it is a very cheap solution to try!

(Full anti-disclosure: I am in no way affiliated with and have never contributed to the dill project.)

Install the package:

pip install dill

Then edit your code to import dill instead of pickle:

# import pickle
import dill as pickle

Run your script and see if it works. (If it does you may want to clean up your code so that you are no longer shadowing the pickle module name!)

Some specifics on datatypes that dill can and cannot serialize, from the project page:

dill can pickle the following standard types:

none, type, bool, int, long, float, complex, str, unicode, tuple, list, dict, file, buffer, builtin, both old and new style classes, instances of old and new style classes, set, frozenset, array, functions, exceptions

dill can also pickle more ‘exotic’ standard types:

functions with yields, nested functions, lambdas, cell, method, unboundmethod, module, code, methodwrapper, dictproxy, methoddescriptor, getsetdescriptor, memberdescriptor, wrapperdescriptor, xrange, slice, notimplemented, ellipsis, quit

dill cannot yet pickle these standard types:

frame, generator, traceback

0

I see no mention here of serial versioning or backcompat, so I will post my solution which I've been using for a bit. I probably have a lot more to learn from, specifically Java and Javascript are probably more mature than me here but here goes

https://gist.github.com/andy-d/b7878d0044a4242c0498ed6d67fd50fe

Fletch F Fletch
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0

To add another option: You can use the attrs package and the asdict method.

class ObjectEncoder(JSONEncoder):
    def default(self, o):
        return attr.asdict(o)

json.dumps(objects, cls=ObjectEncoder)

and to convert back

def from_json(o):
    if '_obj_name' in o:
        type_ = o['_obj_name']
        del o['_obj_name']
        return globals()[type_](**o)
    else:
        return o

data = JSONDecoder(object_hook=from_json).decode(data)

class looks like this

@attr.s
class Foo(object):
    x = attr.ib()
    _obj_name = attr.ib(init=False, default='Foo')
machinekoder
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0

In addition to the Onur's answer, You possibly want to deal with datetime type like below.
(in order to handle: 'datetime.datetime' object has no attribute 'dict' exception.)

def datetime_option(value):
    if isinstance(value, datetime.date):
        return value.timestamp()
    else:
        return value.__dict__

Usage:

def toJSON(self):
    return json.dumps(self, default=datetime_option, sort_keys=True, indent=4)
Mark Choi
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-1

I chose to use decorators to solve the datetime object serialization problem. Here is my code:

#myjson.py
#Author: jmooremcc 7/16/2017

import json
from datetime import datetime, date, time, timedelta
"""
This module uses decorators to serialize date objects using json
The filename is myjson.py
In another module you simply add the following import statement:
    from myjson import json

json.dumps and json.dump will then correctly serialize datetime and date 
objects
"""

def json_serial(obj):
    """JSON serializer for objects not serializable by default json code"""

    if isinstance(obj, (datetime, date)):
        serial = str(obj)
        return serial
    raise TypeError ("Type %s not serializable" % type(obj))


def FixDumps(fn):
    def hook(obj):
        return fn(obj, default=json_serial)

    return hook

def FixDump(fn):
    def hook(obj, fp):
        return fn(obj,fp, default=json_serial)

    return hook


json.dumps=FixDumps(json.dumps)
json.dump=FixDump(json.dump)


if __name__=="__main__":
    today=datetime.now()
    data={'atime':today, 'greet':'Hello'}
    str=json.dumps(data)
    print str

By importing the above module, my other modules use json in a normal way (without specifying the default keyword) to serialize data that contains date time objects. The datetime serializer code is automatically called for json.dumps and json.dump.

John Moore
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-2

There are many approaches to this problem. 'ObjDict' (pip install objdict) is another. There is an emphasis on providing javascript like objects which can also act like dictionaries to best handle data loaded from JSON, but there are other features which can be useful as well. This provides another alternative solution to the original problem.

innov8
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