How to make a variable global without the global keyword?

Asked Jun 07 '16 at 14:41

Active Jun 07 '16 at 14:49

Viewed 68 times

I have a variable called A, and two functions, here some code to follow all along:

def foo():
    a = 1
def bar():
    b = a + 2
    print b
foo()
bar()

This is a minimal basic example that explain my situations. Normally, In order to use a in the function bar(), either we mark a as global or we return it, or we can define a outside of the function (global scope). In my case I can't do any one of these.

Is there any other way to be able to access a in bar?

edited Jun 07 '16 at 14:49

Bhargav Rao

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asked Jun 07 '16 at 14:41

DeltaWeb

1

Return it from `foo`. There's not another way. – Morgan Thrapp Jun 07 '16 at 14:44
`globals()["a"] = 1`? :-) – kindall Jun 07 '16 at 14:54
This is one of the ways where we can avoid both `global`s and `return`s. http://ideone.com/ZieCEa – Bhargav Rao Jun 07 '16 at 14:55
Why do you want to use globals? And even worse, why do you want to make it hard to tell you are using globals? – joel goldstick Jun 07 '16 at 15:05
Sorry, but did you even read the question ? I'm looking for a way to use them with out global .... I DON'T WANT TO USE gloabals . – DeltaWeb Jun 07 '16 at 15:07
"How to make a variable global without the global keyword?" does not convey the idea that you don't want to use globals. – kindall Jun 09 '16 at 05:01

How to make a variable global without the global keyword?

0 Answers0