Passing optional arguments to a function

Question

I would like to pass an undefined number of optional arguments to a function. The optional arguments are stored a priori in a dictionary.

As an example:

def f(a=0, b=0, c=0):
    return a

my_args = {'a':5, 'b':3}

print(f(my_args))

The expected output would be 5, however it is {'a':5, 'b':3}

Answer 1

You need to unpack the dict:

print(f(**my_args))