Javascript: Why does ["2","3"].map(parseInt) return [2, NaN]?

Question

Since map callback gets called on each element, I would have expected [2,3] as the return value based on the documentation here.

Please use the search before asking a new question: [`[javascript] map parseInt`](https://stackoverflow.com/search?q=%5Bjavascript%5D+map+parseInt) — Felix Kling, May 10 '16 at 15:13
This question was discussed recently. The issue is that parseInt takes 2 parameters, expression to evaluate and radix (10 by default). Change to ["3","2"].map(parseInt) and receive [11,NaN] — Alex Kudryashev, May 10 '16 at 15:18

score 1 · Answer 1 · answered May 10 '16 at 15:16

1

Simply use .map(Number) for this type of task:

var a = ["2", "3"];

var b = a.map(Number);

answered May 10 '16 at 15:16

omarjmh

1 Answers1