how to check AccessibilityService

Question

I want to check my AccessibilityService ,but my code have error,below is my code

public static boolean isAccessibilityOn(Context context) {
        int accessibilityEnable = 0;
        try {
            accessibilityEnable = Settings.Secure.getInt(context.getContentResolver(),
                    Settings.Secure.ACCESSIBILITY_ENABLED);
        } catch (Settings.SettingNotFoundException e) {
            e.printStackTrace();
        }

        if (accessibilityEnable == 1) {
            String services = Settings.Secure.getString(context.getContentResolver(),
                    Settings.Secure.ENABLED_ACCESSIBILITY_SERVICES);
            if (services != null) {
                return services.toLowerCase().contains(context.getPackageName().toLowerCase());
            }
        }

        return false;
    }

and this is my error

android.provider.Settings$SettingNotFoundException: accessibility_enabled

I run my demo in api22

score 5 · Accepted Answer · edited Oct 21 '16 at 17:42

Below is the method to check if your accessibility service is enabled or not.

Note: Change value of YOURAccessibilityService with your Service.

// To check if service is enabled
private boolean isAccessibilitySettingsOn(Context mContext) {
    int accessibilityEnabled = 0;
    final String service = getPackageName() + "/" + YOURAccessibilityService.class.getCanonicalName();
    try {
        accessibilityEnabled = Settings.Secure.getInt(
                mContext.getApplicationContext().getContentResolver(),
                android.provider.Settings.Secure.ACCESSIBILITY_ENABLED);
        Log.v(TAG, "accessibilityEnabled = " + accessibilityEnabled);
    } catch (Settings.SettingNotFoundException e) {
        Log.e(TAG, "Error finding setting, default accessibility to not found: "
                + e.getMessage());
    }
    TextUtils.SimpleStringSplitter mStringColonSplitter = new TextUtils.SimpleStringSplitter(':');

    if (accessibilityEnabled == 1) {
        Log.v(TAG, "***ACCESSIBILITY IS ENABLED*** -----------------");
        String settingValue = Settings.Secure.getString(
                mContext.getApplicationContext().getContentResolver(),
                Settings.Secure.ENABLED_ACCESSIBILITY_SERVICES);
        if (settingValue != null) {
            mStringColonSplitter.setString(settingValue);
            while (mStringColonSplitter.hasNext()) {
                String accessibilityService = mStringColonSplitter.next();

                Log.v(TAG, "-------------- > accessibilityService :: " + accessibilityService + " " + service);
                if (accessibilityService.equalsIgnoreCase(service)) {
                    Log.v(TAG, "We've found the correct setting - accessibility is switched on!");
                    return true;
                }
            }
        }
    } else {
        Log.v(TAG, "***ACCESSIBILITY IS DISABLED***");
    }

    return false;
}

And to call this method:

if (!isAccessibilitySettingsOn(getApplicationContext())) {
    startActivity(new Intent(Settings.ACTION_ACCESSIBILITY_SETTINGS));
}

this will check your setting is enabled and if it's not then it will enable it

no ,i use your code ,it also has that error,i run my demo in api22 — jevely, May 02 '16 at 04:39
Did you replce youclass name here "final String service = getPackageName() + "/" + YOURAccessibilityService.class.getCanonicalName();" — satya prakash, May 02 '16 at 04:42
yes , i use my Service name , but only in api22 has this error. — jevely, May 02 '16 at 04:44
yes.. sry it's look like they have changed their methods in api 22 so u have to go thourgh their doc one more time — satya prakash, May 02 '16 at 05:17
Did you copy from [this answer](https://stackoverflow.com/a/18095283/8170714)? At least state your sources next time. — Jack, Oct 07 '20 at 07:56

how to check AccessibilityService

1 Answers1