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How to save stream as image and store the image in temp files?

banupriya
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5 Answers5

38

Try 

Image img = System.Drawing.Image.FromStream(myStream);

img.Save(System.IO.Path.GetTempPath() + "\\myImage.Jpeg", ImageFormat.Jpeg);
Filip Ekberg
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Unmesh Kondolikar
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  • The image step is not necessary. We can write the stream directly to a file. –  Sep 06 '10 at 12:18
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    Yes .. But I assumed that banupriyavijay wants to so something with the image in the application. Otherwise it would be just a file copy operation which can be done using System.IO.File.Copy(). – Unmesh Kondolikar Sep 06 '10 at 12:40
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    When i write this line Image img = System.Drawing.Image.FromStream(stream); it gives me an error "Parameter is not valid." – Chirag Sep 23 '15 at 09:46
  • this solution has issues if you are trying to override an image. I am getting a A Generic error occurred in GDI+ – Juan Zamora Oct 03 '17 at 01:33
6
var tempFile = Path.GetTempFileName();
using (var fs = File.Create(tempFile))
{
   source.copyTo(fs);
}

where source is source stream. Now your source stream is saved at temp location (given by tempFile). Note that file name extension will be TMP.

VinayC
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    +1 for the Path.GetTempFileName() that I didn't know it ever existed. –  Sep 06 '10 at 12:01
  • FileStream does not contain a definition for Create!! Moreover the stream which i use as input is System.IO.Stream and I want to store this IO stream to image in temp files. – banupriya Sep 06 '10 at 12:14
  • Sorry for that - I mean to say File.Create and not FileStream.Create. Will edit the answer. Source stream can be of any stream. – VinayC Sep 06 '10 at 12:48
3

Your stream (image) is stream in the code below.

using (Stream output = new FileStream ("mycat.jpg"))
{
    byte[] buffer = new byte[32*1024];
    int read;

    while ( (read=stream.Read(buffer, 0, buffer.Length)) > 0)
    {
        output.Write(buffer, 0, read);
    }
}

This code is copyrighted by Jon Skeet My contribution is the name of the file ;)

Community
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1

Have a look at the Bitmap Class. There's a constructor overload that takes a Stream as parameter and there's a method called Save which you can use to save it as a file.

Filip Ekberg
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  • The bitmap step is not necessary. We can write the stream directly to a file. –  Sep 06 '10 at 12:18
0

For windows phone 8.1 I found the following to work well. Create your TempStorageFile at whatever path you would like and then pass in your image's stream like so:

var fileStream = await TempStorageFile.OpenAsync(Windows.Storage.FileAccessMode.ReadWrite);
            await RandomAccessStream.CopyAsync(imageStream, fileStream);
ickydime
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