Bash AWK, get first and second output (int)

Question

I have a script where I write the score to a file, named log.txt

In this file I save the score like this: (number 1 is just a example)

Won: 1
Lose: 1

I've written this AWK command:

gameswon=`awk -F : '{print $2}' "$file"`

It gives me this result:

1 1

How can I save the first number to, "won" And the second number to "lose"

Hope anyone can help me

Was it really necessary to use an image for that simple output? Can't you just paste a line of text? — Barmar, Apr 06 '16 at 23:20

score 1 · Accepted Answer · edited Apr 07 '16 at 01:28

1

You can use a bash array:

gameswon=($(awk -F: '{print $2}' "$file"))
won=${gameswon[0]}
lose=${gameswon[1]}

This puts the output of awk -F: '{print $2}' "$file" into the array $gameswon

edited Apr 07 '16 at 01:28

Adam Katz

answered Apr 06 '16 at 23:20

Barmar

score 0 · Answer 2 · answered Apr 06 '16 at 22:51

0

You can use read with little modifier awk in process substitution:

read -r won lose < <(awk -F : '$1 ~ /^(Won|Lose)$/{printf "%s ", $2+0}' "$file")

answered Apr 06 '16 at 22:51

anubhava

2 Answers2