Javascript nth occurance of a string and extract the sub string upto that

Question

Suppose I have a string like this

var str = 'E2*2001/116*0364*31'

What I want is to find the 3rd occurrence of * in the string and print up to that from starting.

So result would be E2*2001/116*0364*

I have tried something like this jsfiddle.

Corresponding code

var str = 'E2*2001/116*0364*31',
delimiter = '*',
start = 0,
var pos=getPosition(str, *, 3);
alert(pos);
tokens = str.substring(start, getPosition(str,*,3)),
result = tokens;


document.body.innerHTML = result;


function getPosition(str, m, i) {
   return str.split(m, i).join(m).length;
}

But unable to get the output.

Can anyone please assist.

Possible duplicate of [Cutting a string at nth occurrence of a character](http://stackoverflow.com/questions/5494691/cutting-a-string-at-nth-occurrence-of-a-character) — Hanky Panky, Apr 05 '16 at 08:00

score 2 · Accepted Answer · answered Apr 05 '16 at 08:07

2

Try this.

str.split('*').slice(0,3).join('*') + '*';

answered Apr 05 '16 at 08:07

Lewis

13,134
12
62
81

Qwertiy · Answer 2 · 2016-04-05T08:10:05.473

1

var str = 'E2*2001/116*0364*31';
console.log(str.match(/^([^*]*\*){3}/)[0]);              // E2*2001/116*0364*
console.log(str.match(/^([^*]*\*){3}/)[0].slice(0, -1)); // E2*2001/116*0364

edited Apr 05 '16 at 08:10

answered Apr 05 '16 at 08:05

Qwertiy

17,208
13
50
117

it does not give me last * – Navoneel Talukdar Apr 05 '16 at 08:07
@Neel, neither your code in the question. If you need last `*` just remove `.slice(0, -1)`. – Qwertiy Apr 05 '16 at 08:08
1

@JonathanBrooks, fixed. – Qwertiy Apr 05 '16 at 08:10
may be you need to mention that this solution requires `regex` – Rajshekar Reddy Apr 05 '16 at 08:13
1

@Reddy, isn't it clear from regex literal in the code? – Qwertiy Apr 05 '16 at 08:24
@Qwertiy its only because the OP doesn't have a `regex` tag added to it. Also we cant be sure that beginners can even identify that literal as a `regex'. – Rajshekar Reddy Apr 05 '16 at 09:46

score 0 · Answer 3 · answered Apr 05 '16 at 11:18

0

A solution with String#replace:

var string = 'E2*2001/116*0364*31'.replace(/([^*]+\*){3}/, '');
document.write('<pre>' + JSON.stringify(string, 0, 4) + '</pre>');

answered Apr 05 '16 at 11:18

Nina Scholz

351,820
24
303
358

Javascript nth occurance of a string and extract the sub string upto that

3 Answers3

Related