what will be output of the following code and why ? can anyone explain?

Question

#include <stdio.h>

int main()
{
    int i = 6;
    printf("%d %d", ++i, i++);//printing
    return 0;
}

What will be output of the following code and why?

Answer 1

printf("%d %d",++i ,i++);//printing

Is undefined behavior. The order of argument processing is not specifically defined in the C standard, it is not possible to predict exactly what the output will be. It could be anything at all according to this.