Syntax error near an equal sign

Question

I don't know why it does this. Here's the code.

ac1 = input('1=Jab, 2=Punch, 3=Kick, or 4=Taunt?: ')
if ac1 = 1:
    print('You jab at Apollo Creed. He dodges it.')
    print('Apollo Creed continues to taunt.')

I'm making a Text based game based on the Rocky movies. :D the 1=jab and stuff means One equals Jab (if you type 1, you jab.)

Selcuk · Answer 1 · 2016-03-06T04:16:34.823

1

Single = sign is assignment. Equality is double =:

if ac1 == 1:

edited Mar 06 '16 at 04:16

answered Mar 06 '16 at 04:16

Selcuk

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@Lava `input` returns a string, so you'll need to quote the 1 – OneCricketeer Mar 06 '16 at 04:18
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@Lava if this answer is correct, please mark it as such, for future programmers. – Joseph Farah Mar 06 '16 at 04:47
@cricket_007 The OP is using Python 3.x, so input returns an int. – Selcuk Mar 06 '16 at 06:57
@Selcuk - I don't think so. Then again, I do most stuff in Python2... http://stackoverflow.com/a/20449433/2308683 – OneCricketeer Mar 06 '16 at 07:12

99lives · Answer 2 · 2016-03-06T04:24:22.647

1

You are using a single equals sign, this is used to set variables.

Use double equals == to check if a variable is equal to something.

ac1 = input('1=Jab, 2=Punch, 3=Kick, or 4=Taunt?: ')
if ac1 == 1:
    print('You jab at Apollo Creed. He dodges it.')
    print('Apollo Creed continues to taunt.')

edited Mar 06 '16 at 04:24

answered Mar 06 '16 at 04:18

99lives

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Syntax error near an equal sign

2 Answers2