Java function signature for (() -> {})

Question

What's a valid function signature for funSig?

funSig(() -> System.out.println());

May be related: [How do I define a method which takes a lambda as a parameter in java 8](http://stackoverflow.com/questions/13604703/how-do-i-define-a-method-which-takes-a-lambda-as-a-parameter-in-java-8) — NiziL, Mar 04 '16 at 14:55
Possible duplicate of [Java 8 lambda Void argument](http://stackoverflow.com/questions/29945627/java-8-lambda-void-argument) — Jean-François Savard, Mar 04 '16 at 14:58
this question is legitimate. It should have not been closed. — Zo72, Nov 28 '16 at 13:44

Sleiman Jneidi · Accepted Answer · 2016-03-04T14:58:47.803

7

A Runnable would work,

It matches a void return and no params.

Runnable runnable = () -> System.out.println();

And obviously it doesn't need to be Runnable, any Functional Interface that matches the signature will do.

edited Mar 04 '16 at 14:58

answered Mar 04 '16 at 14:53

Sleiman Jneidi

1

thanks, for some reason I was looking for an interface in `java.util.function` – Stefan K. Mar 04 '16 at 14:56

1 Answers1