Python check if string contains all words in Python

Question

I want to check if all words are found in another string without any loops or iterations:

a = ['god', 'this', 'a']

sentence = "this is a god damn sentence in python"

all(a in sentence)

should return TRUE.

this could help http://stackoverflow.com/questions/3389574/check-if-multiple-strings-exist-in-another-string — Allen Fernandes, Feb 10 '16 at 14:21

Martin Evans · Answer 1 · 2016-02-10T14:52:33.273

4

You could use a set depending on your exact needs as follows:

a = ['god', 'this', 'a']
sentence = "this is a god damn sentence in python"

print set(a) <= set(sentence.split())

This would print True, where <= is issubset.

edited Feb 10 '16 at 14:52

answered Feb 10 '16 at 14:32

Martin Evans

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You could drop the `' '` to become `set(sentence.split())` – Rolf of Saxony Feb 10 '16 at 14:51

Iron Fist · Answer 2 · 2016-02-10T15:17:27.947

3

It should be:

all(x in sentence for x in a)

Or:

>>> chk = list(filter(lambda x: x not in sentence, a)) #Python3, for Python2 no need to convert to list
[] #Will return empty if all words from a are in sentence
>>> if not chk:
        print('All words are in sentence')

edited Feb 10 '16 at 15:17

answered Feb 10 '16 at 14:31

Iron Fist

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That's part of `all` expression...nothing to do about it, but I don't believe that's part of OP concern...as he is avoiding any explicit `for` loop – Iron Fist Feb 10 '16 at 14:47

Python check if string contains all words in Python

2 Answers2