Looking through stdarg.h, I spotted the following:
#if !defined(__STRICT_ANSI__) || __STDC_VERSION__ + 0 >= 199900L
#define va_copy(d,s) __builtin_va_copy(d,s)
#endif
Is there a purpose to adding 0 in the expression?
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Trevor Hickey
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`stdarg.h` from which toolchain or system ? – njuffa Jan 29 '16 at 22:12
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Most compilers will just ignore this. It may be some left over code from some previous implementation or it may be something that was done to convince a specific compiler to treat this however the programmer intended.
acid1789
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