Await the result of Task using reflection in a non-generic method

Question

Consider the following case:

class A
{
    public int Id;
}

class B : A
{

}

class Main
{
    public async Task<int> Create(Type type)
    {
        MethodInfo method = this.GetType().GetMethod("Create", new Type[] { typeof(string) }).MakeGenericMethod(new Type[] { type });
        A a = await (Task<A>)method.Invoke(this, new object[] { "humpf" });
        return a.Id;
    }

    public async Task<T> Create<T>(string name) where T : A
    {
        T t = await Foo.Bar<T>(name);
        return t;
    }
}

Calling new Main().Create(typeof(B)) will fail with a

Unable to cast object of type 'System.Threading.Tasks.Task[B]' to type 'System.Threading.Tasks.Task[A]'

I don't quite understand because in this case, the Generic Create<T> method can only return a Task<T> where T is always derived from 'A', but maybe I'm missing an edge case here. Besides that, how can I make this work? Thanks!

Unlike interfaces, concrete types such as `Task` cannot be covariant. See [Why is Task not co-variant?](http://stackoverflow.com/questions/30996986/why-is-taskt-not-co-variant). So `Task` cannot be assigned to a `Task`. — Lukazoid, Jan 15 '16 at 15:52
Thanks for that link! That helps. Now how do I work around this? :-) — Razzie, Jan 15 '16 at 15:56

score 25 · Accepted Answer · edited May 23 '17 at 11:45

25

As per my comment:

Unlike interfaces, concrete types such as Task<TResult> cannot be covariant. See Why is Task not co-variant?. So Task<B> cannot be assigned to a Task<A>.

The best solution I can think of is to use the underlying type Task to perform the await like so:

var task = (Task)method.Invoke(this, new object[] { "humpf" });
await task;

Then you can use reflection to get the value of the Result:

var resultProperty = typeof(Task<>).MakeGenericType(type).GetProperty("Result");
A a = (A)resultProperty.GetValue(task);
return a.Id;

edited May 23 '17 at 11:45

Community

1
1

answered Jan 15 '16 at 15:57

Lukazoid

18,199
3
62
83

Why not just `task.GetType()` instead of `typeof(Task<>).MakeGenericType(type)` ? – huysentruitw Aug 10 '17 at 14:18
2

`task.GetType()` would most likely always be fine, but if the resulting `Task` was a derived type which shadowed `Result` it would throw an `AmbiguousMatchException`. Like this that can never possibly happen as I am being more explicit over where I expect to find the `Result` property. – Lukazoid Aug 10 '17 at 15:27
@JohnLeidegren I have no idea but it's possible, so I think it's safer to cater for that possibility. – Lukazoid May 23 '19 at 09:25
@Lukazoid I'm using reflection to unwrap the task result because I don't know the type. If I knew the type I would just cast the value to `Task`. – John Leidegren May 24 '19 at 20:57
@JohnLeidegren How would you do that cast if you only knew the type at runtime, like in the question? – Lukazoid May 26 '19 at 19:27
@Lukazoid if the type parameter is dynamic you can't. – John Leidegren May 27 '19 at 12:05

onets · Answer 2 · 2021-08-04T13:56:05.850

0

I needed to get task result in Castle Interceptor. This code works for me:

if (invocation.ReturnValue is Task task)
{
    task.Wait();

    var result = invocation.ReturnValue.GetType().GetProperty("Result").GetValue(task);
    _cacheProvider.Set(_key, result, _duration);
}

edited Aug 04 '21 at 13:56

answered Aug 04 '21 at 13:50

onets

61
3

score -1 · Answer 3 · answered Aug 16 '19 at 18:43

The above solution really helped me. I made a small tweak to the @Lukazoid solution...

var resultProperty = typeof(Task<>).MakeGenericType(type).GetProperty("Result");
A a = (A)resultProperty.GetValue(task);

to

dynamic a = task.GetType().GetProperty("Result")?.GetValue(task);

Await the result of Task using reflection in a non-generic method

3 Answers3

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