PHP: date "Yesterday", "Today"

Question

I have a little function that shows latest activity, it grab timestamp in unix format from the db, and then it echo out with this line:

 date("G:i:s j M -Y", $last_access)

Now i would like to replace the date (j M -Y) to Yesterday, and Today if the latest activity was within today, and same goes with Yesterday.

How can i do this?

Can you please try to be more precise? I haven't understood what you mean by Yesterday and Today... frankly ;-) — maraspin, Aug 10 '10 at 23:36
It's tomorrow you need to worry about, not yesterday or today, clearing away all those cobwebs and the sorrow, just knowing it's a day away and all that. — , Aug 10 '10 at 23:42

Hameed · Answer 1 · 2016-03-17T03:47:05.953

44

I would find the timestap for last midnight and the one before it, if $last_access is between the two timestamps, then display yesterday, anything greater than last midnight's timestamp would be today...

I believe that would be the quicker than doing date arithmetic.

Actually, I just tested this code and it seems to work great:

<?php
    if ($last_access >= strtotime("today"))
        echo "Today";
    else if ($last_access >= strtotime("yesterday"))
        echo "Yesterday";
?>

edited Mar 17 '16 at 03:47

answered Aug 10 '10 at 23:38

Hameed

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Much cleaner than my answer +1 – Keyo Oct 14 '10 at 23:54

score 15 · Accepted Answer · edited Dec 12 '15 at 05:49

15

function get_day_name($timestamp) {

    $date = date('d/m/Y', $timestamp);

    if($date == date('d/m/Y')) {
      $date = 'Today';
    } 
    else if($date == date('d/m/Y',now() - (24 * 60 * 60))) {
      $date = 'Yesterday';
    }
    return $date;
}
print date('G:i:s', $last_access).' '.get_day_name($last_access);

edited Dec 12 '15 at 05:49

Shahzad Barkati

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answered Aug 10 '10 at 23:54

Keyo

13,157
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1

The `else if` line seems to be missing a `)`. – Maerlyn Aug 11 '10 at 00:25
Sorry, fixed that up for you Karem. I guess it worked out for you though. – Keyo Aug 11 '10 at 03:09
7

Function now() does not exists. Use time() – ilya iz Mar 07 '12 at 08:47
It's probably easier to once get the number of days away from now instead, so the same value can be used twice. – hakre Jun 16 '12 at 11:12
1

shouldn't it be `return $day_name;` ? – Paulo Bueno Jan 03 '14 at 18:42
[Here](http://tehplayground.com/#Q9l2dASlD) is a modified (and **working**) code of example provided in above post. I also added option of a 'day before yesterday' and parameter, that adds time to day name. – Kudlas Sep 17 '15 at 08:13

score 10 · Answer 3 · answered Jul 24 '13 at 12:41

You have to compare day with day, secondes comparaison are totally wrong :

If we are today morning, that means yesterday night is today (by minus 24h) ^^

Here a method I use for Kinoulink ( a french startup ) :

public function formatDateAgo($value)
{
    $time = strtotime($value);
    $d = new \DateTime($value);

    $weekDays = ['Lundi', 'Mardi', 'Mercredi', 'Jeudi', 'Vendredi', 'Samedi', 'Dimanche'];
    $months = ['Janvier', 'Février', 'Mars', 'Avril',' Mai', 'Juin', 'Juillet', 'Aout', 'Septembre', 'Octobre', 'Novembre', 'Décembre'];

    if ($time > strtotime('-2 minutes'))
    {
        return 'Il y a quelques secondes';
    }
    elseif ($time > strtotime('-30 minutes'))
    {
        return 'Il y a ' . floor((strtotime('now') - $time)/60) . ' min';
    }
    elseif ($time > strtotime('today'))
    {
        return $d->format('G:i');
    }
    elseif ($time > strtotime('yesterday'))
    {
        return 'Hier, ' . $d->format('G:i');
    }
    elseif ($time > strtotime('this week'))
    {
        return $weekDays[$d->format('N') - 1] . ', ' . $d->format('G:i');
    }
    else
    {
        return $d->format('j') . ' ' . $months[$d->format('n') - 1] . ', ' . $d->format('G:i');
    }
}

Great! It's only missing the year, at the last «else». But it's a beauty. Thanks! — Pedro Ferreira, Oct 04 '16 at 12:53

score 4 · Answer 4 · answered Nov 21 '17 at 10:36

I enhanced Thomas Decaux answer to come up with this

function formatTimeString($timeStamp) {
$str_time = date("Y-m-d H:i:sP", $timeStamp);
$time = strtotime($str_time);
$d = new DateTime($str_time);

$weekDays = ['Mon', 'Tue', 'Wed', 'Thur', 'Fri', 'Sat', 'Sun'];
$months = ['Jan', 'Feb', 'Mar', 'Apr', ' May', 'Jun', 'Jul', 'Aug', 'Sept', 'Oct', 'Nov', 'Dec'];

if ($time > strtotime('-2 minutes')) {
  return 'Just now';
} elseif ($time > strtotime('-59 minutes')) {
  $min_diff = floor((strtotime('now') - $time) / 60);
  return $min_diff . ' min' . (($min_diff != 1) ? "s" : "") . ' ago';
} elseif ($time > strtotime('-23 hours')) {
  $hour_diff = floor((strtotime('now') - $time) / (60 * 60));
  return $hour_diff . ' hour' . (($hour_diff != 1) ? "s" : "") . ' ago';
} elseif ($time > strtotime('today')) {
  return $d->format('G:i');
} elseif ($time > strtotime('yesterday')) {
  return 'Yesterday at ' . $d->format('G:i');
} elseif ($time > strtotime('this week')) {
  return $weekDays[$d->format('N') - 1] . ' at ' . $d->format('G:i');
} else {
  return $d->format('j') . ' ' . $months[$d->format('n') - 1] .
  (($d->format('Y') != date("Y")) ? $d->format(' Y') : "") .
  ' at ' . $d->format('G:i');
}

}

It takes in the time stamp as the argument, it adds the year of the time if it was from a different year, etc...

score 3 · Answer 5 · answered Apr 11 '19 at 15:06

3

echo date("Y:m:d",strtotime("today"));
echo date("Y:m:d",strtotime("yesterday"));

answered Apr 11 '19 at 15:06

dılo sürücü

2,921
1
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Hi! While this may be a solution to the question, code only answers are generally discouraged on SO. Please take some time to edit your response with an explanation as to why this is a solution as it will help OP and future visitors of the site. – d_kennetz Apr 11 '19 at 19:23

score 2 · Answer 6 · answered Aug 10 '10 at 23:52

If you are going down the road as suggested above, with unix timestamps for today / yesterday, have a look at strtotime, one of the greatest inventions of the 20th (or 21st?) century:

echo strtotime("yesterday"); // midnight
1281391200

echo strtotime("today"); // midnight
1281477600

echo strtotime("today, 1:30");
1281483000

tcrosley · Answer 7 · 2010-08-11T00:20:54.477

1

something like:

$now = time();

$last_midnight = $now - ($now % (24*60*60));

if ($last_access >= $last_midnight)
{
 print "Today";
}    
elseif ($last_access >= ($last_midnight-(24*60*60))
{
 Print "Yesterday";
}

edited Aug 11 '10 at 00:20

answered Aug 10 '10 at 23:42

tcrosley

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@mvds: I didn't know you could use relative strings in strtotime. Nice. Some gotchas re PHP4 vs PHP5 though. – tcrosley Aug 11 '10 at 00:17
I actually use it in some web based search service to allow the user to enter a sliding window: e.g. from "two months ago" to "today". – mvds Aug 11 '10 at 00:25

score 0 · Answer 8 · answered Jan 31 '17 at 08:43

0

here's working function

    function minus_one_day($date){
      $date2 = formatDate4db($date);
      $date1 = str_replace('-', '/', $date2);
      $yesterday = date('Y-m-d',strtotime($date1 . "-1 days"));
      return $yesterday; }

hope work for you...

answered Jan 31 '17 at 08:43

Muhammad Awais Zulifqar

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3
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score 0 · Answer 9 · answered Apr 11 '19 at 13:38

0

$today=new DateTime('now');
$yesterday=date($today,strtotime("-1 day"));

answered Apr 11 '19 at 13:38

dılo sürücü

2,921
1
15
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Can you explain that further? Most other answers need some kind of comparison to print either `Yesterday` or `Today`, but your code is missing it - are you sure this solves the given problem? – Nico Haase Apr 11 '19 at 15:03
$today=new DateTime('now'); $yesterday=date($today,strtotime("-1 day")); maybe not wokıing ... – dılo sürücü Apr 11 '19 at 15:07
That looks like the same code you've posted in your answer. But how does it print something? How does it print either the exact string `Yesterday` or `Today`? – Nico Haase Apr 11 '19 at 15:08

PHP: date "Yesterday", "Today"

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