Is there any function to find the mode (or multiple if more than 1 value occurs most) of a list in Python 2.6?

Question

I have an input list, say x = [1,1,2,1,4,3,5,3,3] and I want to find the mode using Python 2.6.

Google so far gives me only answers such as Counter, statistics and mode() which all work for Python 2.7 and higher, but not 2.6.

My question now is: would anyone know how to easily calculate the mode(s) of such a list without programming the whole function itself?

Yeah you are right Kevin! I'm just curious if there are built-in functions — Fraukje, Dec 23 '15 at 14:46

score 2 · Accepted Answer · edited May 23 '17 at 12:15

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If you're doing statistical work, you might already have scipy installed. If that's the case, you can use scipy.stats.mode.

If not, you'll need to write your own function or get one from some other 3rd party library since there isn't one in the standard library in python2.6.

Also, apparently, scipy.stats.mode only depends on numpy, so you could just copy the source for that if you have numpy but don't want to download scipy . . .

edited May 23 '17 at 12:15

Community

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answered Dec 23 '15 at 14:42

mgilson

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Thanks, this was the answer I was looking for! – Fraukje Dec 23 '15 at 14:48

Mukund M K · Answer 2 · 2015-12-23T15:17:03.590

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x = [1,1,2,1,4,3,5,3,3]
print [i for i in set(x) if x.count(i) == max(map(x.count, x))]

result:

[1, 3]

if you need to reuse, maybe a lambda function:

mode = lambda x: [i for i in set(x) if x.count(i) == max(map(x.count, x))]
x = [1,1,2,1,4,3,5,3,3]
print mode(x)

edited Dec 23 '15 at 15:17

answered Dec 23 '15 at 14:50

Mukund M K

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This one does not give me the required result: both 1 and 3 occur 3x, so it should output both 1 and 3. – Fraukje Dec 23 '15 at 14:53
Although O(N²). You can do better than that. :-) – jsbueno Dec 28 '15 at 12:24

score 0 · Answer 3 · answered Dec 23 '15 at 14:37

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If you're averse to writing your own function, check PyPI for possible modules. This one seems to be a likely candidate, but there may be others:

https://pypi.python.org/pypi/Counter/1.0.0

answered Dec 23 '15 at 14:37

Lav

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score 0 · Answer 4 · answered Dec 23 '15 at 14:41

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x= [1,2,3,1,2,4,5]
y = set(x)
countDict = {}
for item in y:
    countDict[item] = x.count(item)

result:

{1: 2, 2: 2, 3: 1, 4: 1, 5: 1}

answered Dec 23 '15 at 14:41

rajesh.kanakabandi

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Is there any function to find the mode (or multiple if more than 1 value occurs most) of a list in Python 2.6?

4 Answers4